Ask question

Ask question

All categories

3 years ago

11

There are 14 marbles in a blue jar. The blue jar has 7 times as many marbles as a red jar. Let m be the number of marbles in the

red jar

1 answer:

Oksi-84 [34.3K]3 years ago

6 0

Answer:

b=blue jar

Step-by-step explanation:

b=7m

You might be interested in

PPLLLLZZZZZ HHHEEELLLLPPPP

Phantasy [73]

Answer:

11 1/3 sq yards

Step-by-step explanation:

4 1/4 x 2 2/3

change into improper fractions: 17/4 x 8/3 = 136/12 = 11 1/4

3 0

3 years ago

What is the equation in point-slope form of a line that passes through the points (5, −3)(5, −3) and (−2, 9)(−2, 9) ?

Alina [70]

Point sloe is
y-y1=m(x-x1)
slope=m
a ponint is (x1,y1)

slope=(y2-y1)/(x2-x1)
(x,y)
(5,-3)
(-2,9)
slope=(9-(-3))/(-2-5)=12/-7=-12/7
m=-12/7

a point is (5,-3)
x1=5
y=-3
y-(-3)=-12/7(x-5)
y+3=-12/7(x-5)

2nd one

5 0

3 years ago

Erin's family has completed 70% of a trip. They have traveled 35 miles.<br> How far is the trip?

Alexxandr [17]

Answer:

Their trip is 50 mile long.

Step-by-step explanation:

I first divided 70 by 35 to get two.The two represents 1 mile = 2%. So then I subtracted 70 from 100 to get 30 then I divided 30 by 2 to get 15. Then I added 15 to the original 35 to get 50 miles for their 100%/destination of their trip. Hope this helps! Have a great day!

7 0

3 years ago

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
\\
\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0
\\
\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
\\
\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}
\\
\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
\\
\\y' = \frac{3}{( -32 )}$

7 0

3 years ago

The coach of a baseball team separates the players into groups for drills.Each group has the same number of players. Is the tota

scZoUnD [109]

Answer:it is composite

Step-by-step explanation:

it is composite because if there is say 60 people on the team and he divided the groups amongst three people in each group then it would be 20 groups now that isn't prime see so it would be the same thing if the basketball coach separates the team into 10 groups and there's 60 people on that team that's not a prime number that would be a composite number so the answer is composite A prime number would be there's eight people in each group and he separates them into a group so that means that They would be 64 people on that team Now the book that I'm looking at right now doesn't tell you the people on that team and how much people there are on that team but it says there is a different amount from The number of teams to the number of people in the team see there's like eight people in the team and there is for groups so that means two people in each group so That means that the answer would have to be composite and not prime hope this helped somebody.

7 0

3 years ago