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satela [25.4K]
3 years ago
5

What are all the factors of 47?

Mathematics
1 answer:
nikklg [1K]3 years ago
5 0
The factors are 1 and 47, since 47 is a prime number.
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Which absolute value represents a number less than |−0.14|
jasenka [17]

Answer:

See explanation

Step-by-step explanation:

The given absolute value is

| - 0.14|

When we simplify this we get:

| - 0.14|  = 0.14

Any absolute value expression whose value is less than 0.14 is a solution.

For instance :

| - 0.1|

|0.05|

| - 0.006|

are all less than the 0.14

Since you haven't provided the options, we can't provide an exact answer.

Please remember to post a complete question next time.

3 0
3 years ago
ANSWER ASAP !!!!!!!!!!
tekilochka [14]
Option C is correct or y=3/4x-5. Use the given functions to set up and simplify y=mx+b
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3 years ago
Find the area of the circle whose equation is x2+y2=6x-8y​
Semenov [28]

Answer:

Given that the equation of a circle is :

\green{ \boxed{\boxed{\begin{array}{cc}  {x}^{2}  +  {y}^{2}  = 6x - 8y \\  =  >  {x}^{2}  +  {y}^{2}   - 6x + 8y = 0 \\  =  >  {x}^{2}  +  {y}^{2}  + 2 \times ( - 3) \times x + 2 \times 4 \times y = 0 \\  \\  \sf \: standard \: equation \: o f \: circle \: is :  \\   {x}^{2}  +  {x}^{2}  + 2gx + 2fy + c = 0 \\  \\  \sf \: by \: comparing \\  \\ g =  - 3 \\ f = 4 \\ c = 0 \\  \\  \sf \: radius \:  \: r =  \sqrt{ {g}^{2}  +  {f}^{2} - c }  \\  =  \sqrt{ {( - 3)}^{2} +  {4}^{2} - 0  }  \\  =  \sqrt{9 + 16}  \\   = \sqrt{25}  \\  = 5 \: unit \\  \\  \bf \: area \:  = \pi {r}^{2}  \\  = \pi \times  {5}^{2}  \\  =\pink{ 25\pi \:  { unit }^{2} }\end{array}}}}

6 0
3 years ago
Prove:1/sin²A-1/tan²A=1​
Anit [1.1K]

Step-by-step explanation:

1/sin^2A -cos^2A/sin^2 A. ~tan = sin/cos

(1-cos^2)/sin^2A. ~ take lcm

sin^2A/sin^ A. ~ 1-cos^2A = sin^2A

1

for more free ans check bio

7 0
3 years ago
Read 2 more answers
Surface area of this right prism
Sphinxa [80]

\qquad\qquad\huge\underline{{\sf Answer}}

\textsf{Let's calculate the surface area of given right prism}

\textbf{Area of Triangles :}

  • \sf{\dfrac{1}{2}\cdot 16\cdot 12}

  • \sf{8×12}

  • \sf96 \:  \: cm {}^{2}

\textsf{Since there are two triangles, }

\textsf{Area of Triangles = 96 × 2 = 192 cm²}

\textbf{Now, calculate the Areas of rectangles :}

  • \textsf{Area - 1 = 12 × 10 = 120 cm²}

  • \textsf{Area - 2 = 16 × 10 = 160 cm²}

  • \textsf{Area - 3 = 20 × 10 = 200 cm²}

\textsf{Now add them all :}

  • \textsf{120 + 160 + 200 + 192}

  • \textsf{672 cm²}

7 0
2 years ago
Read 2 more answers
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