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Sever21 [200]
2 years ago
13

Surface area of this right prism

Mathematics
2 answers:
Sphinxa [80]2 years ago
7 0

\qquad\qquad\huge\underline{{\sf Answer}}

\textsf{Let's calculate the surface area of given right prism}

\textbf{Area of Triangles :}

  • \sf{\dfrac{1}{2}\cdot 16\cdot 12}

  • \sf{8×12}

  • \sf96 \:  \: cm {}^{2}

\textsf{Since there are two triangles, }

\textsf{Area of Triangles = 96 × 2 = 192 cm²}

\textbf{Now, calculate the Areas of rectangles :}

  • \textsf{Area - 1 = 12 × 10 = 120 cm²}

  • \textsf{Area - 2 = 16 × 10 = 160 cm²}

  • \textsf{Area - 3 = 20 × 10 = 200 cm²}

\textsf{Now add them all :}

  • \textsf{120 + 160 + 200 + 192}

  • \textsf{672 cm²}

musickatia [10]2 years ago
7 0

Answer:

Step-by-step explanation:

(16+12+20)*10+16*12= 48*10+192+480+192=672 c.m. squared

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a

Step-by-step explanation:

since 90 degrees is 1/4 of a circle, the area of the sector is 5²pi/4 = 25/4pi = 19.63

5 0
3 years ago
Solve this equation: 4y + 228 = 352. <br> A. y = 31<br> B. y = – 31<br> C. y = 3<br> D. y = 145
V125BC [204]
To let the variable alone you can follow these steps: 1) subtract 228 from both sides 2) divide both sides by 4. This is the solution: 1) 4y + 228 - 228 = 352 - 228 => 2) 4y = 124 => 3) (4y)/4 = 124/4 => 4) y = 31. Then, <span>the answer is the option A. y = 31. </span>
3 0
3 years ago
Drag the simplified value into the box to match each expression.
AveGali [126]

Answer:

2^{3} +1⋅4−3 = 9

2^{0}+10−4⋅2 = 3

3+5^{2} -6⋅4 = 4

Step-by-step explanation:

4 0
2 years ago
"how many different rectangles" can you draw that have a perimeter of 12, 14
amm1812
Perimeter of rectangle = length + length + width + width

To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14

Rectangle with perimeter 12

Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3

Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have

Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have

The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12

length = 4 and width = 2
length = 5 and width = 1
--------------------------------------------------------------------------------------------------------------

Rectangle with perimeter of 14

Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14

Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14

Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14

We can have 3 different combinations of length and width





3 0
3 years ago
AD = 4, BC = 5, AB + DC = 12. Найти AB, DC, AC.
Black_prince [1.1K]

Answer:

Im sorry but I ain't smart for this stuff

Step-by-step explanation:

lol

6 0
3 years ago
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