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Akimi4 [234]
3 years ago
10

Witch number produces a rational number when multipled by 0.25

Mathematics
1 answer:
Hunter-Best [27]3 years ago
4 0

Answer:

1

Step-by-step explanation:

.25 is already a rational number as it equals 25/100 and 1/4 simplified

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What is the percent increase from 126 points to 48 points
svetoff [14.1K]
48-126=-78
-78/126= -0.<span>619047619
-0.</span>619047619x100=<span>61.9047619%
This can be rounded to 62%

Hope this helps :)</span>
6 0
3 years ago
Put a digit in the gap, such that the answer is a whole number:<br> 9x–42=5... I will give brainiest
cestrela7 [59]

9x–42=5 is x = 11.

<u>Step-by-step explanation:</u>

9x- 42 = 5...

When we put x = 9

then we will get 81 - 42 =39

put x = 10 then

9(10) - 42 = 90 - 42 - 48

put x = 11

then 9(11) - 42 = 99-42 = 57

So x = 11 is the answer.

7 0
3 years ago
F(x) = 5x-2, find f(-3/5) what is the output of the given input
Natasha_Volkova [10]
F(x) = 5x - 2
f(-3/5) = 5(-3/5) - 2
f(-3/5) = -15/5 - 2
f(-3/5) = -3 - 2
f(-3/5) = -5
4 0
3 years ago
Pls answer! i will mark brainliest!
Volgvan

Answer:

3 inches

Step-by-step explanation:

(14+2x) × (15+2x) = 2(14×15)

210 +30x +28x + 4x² = 420

4x² + 58x - 210 = 0

2x² + 29x - 105 = 0

2x² + 35x - 6x - 105 = 0

x(2x + 35) - 3(2x + 35) = 0

(x - 3)(2x + 35) = 0

x = 3, -35/2(not possible)

3 0
3 years ago
Hey how do you get from standard form to vertex form?
vlabodo [156]

Explanation:

Conversion of a quadratic equation from standard form to vertex form is done by completing the square method.

Assume the quadratic equation to be \mathbf{ax^{2}+bx+c=0} where x is the variable.

Completing the square method is as follows:

  1. send the constant term to other side of equal                 \mathbf{ax^{2}+bx=-c}
  2. divide the whole equation be coefficient of \mathbf{x^{2}}, this will give     \mathbf{x^{2}+\frac{b}{a}x=- \frac{c}{a}}
  3. add \mathbf{(\frac{b}{2a})^{2}} to both side of equality                                   \mathbf{x^{2}+2\times\frac{b}{2a}x+\frac{b}{2a}^{2}=-\frac{c}{a}+\frac{b}{2a}^{2}}
  4. Make one fraction on the right side and compress the expression on the left side                                                                          \mathbf{(x+\frac{b}{2a})^{2}=\frac{b^{2}-4ac}{4a^{2}}}
  5. rearrange the terms will give the vertex form of standard quadratic equation                                                                 \mathbf{a(x+\frac{b}{2a})^{2}-\frac{b^{2}-4ac}{4a}=0}

Follow the above procedure will give the vertex form.

(NOTE : you must know that \mathbf{(x+a)^{2}=x^{2}+2ax+a^{2}}. Use this equation in transforming the equation from step 3 to step 4)

8 0
3 years ago
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