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3 years ago

12

The formula for the circumference of a circle is c-nd, where d is the length of the diameter. If d is a rational number, what ca

n
you conclude about the circumference?

1 answer:

zimovet [89]3 years ago

6 0

Answer:

could you add a pi

Step-by-step explanation:

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What is mean by probability

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it is the chances of something to happen

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Find the value of x for this trapezoid.

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You just add up all of the sides to find the x

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A 29-meter ladder is sliding down a vertical wall so the distance between the top of the ladder and the ground is decreasing at

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Complete question

A 29-meter ladder is sliding down a vertical wall so the distance between the top of the ladder and the ground is decreasing at 7 meters per minute. At a certain instant, the bottom of the ladder is 21 meters from the wall.

What is the rate of change of the distance between the bottom of the ladder and the wall at that instant(in meters per minute)

Answer:

$\frac{dx}{dt}=11.94m/min$

Step-by-step explanation:

From the question we are told that

Slant height $z=29m$

Change in Vertical height $\triangle y=7m/s$

Horizontal length $x=21$

Generally in finding the distance form the top to the bottom of the wall it is mathematically given by

$x^2+y^2=z^2$

$21^2+y^2=29^2$

$y^2=29^2+21^2$

$y=35.81$

Generally solving for the differential equation is mathematically represented as

$x^2+y^2=29^2$

$2x*\frac{dx}{dt} +2y*\frac{dy}{dt} =0$

$x*\frac{dx}{dt} +y*\frac{dy}{dt} =0$

$(21)*\frac{dx}{dt} +(35.81)*(-7) =0$

$(21)*\frac{dx}{dt} -250.64 =0$

$\frac{dx}{dt}=\frac{250.64}{21}$

$\frac{dx}{dt}=11.94m/min$

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3 years ago

If cosine theta equals negative square root of three over two and pi over two less than theta less than pi, what are the values

Natalka [10]

<h2>Answer:</h2>

The values of sinθ and tanθ are:

$\sin \theta=\dfrac{1}{2}$

and

$\tan \theta=-\dfrac{1}{\sqrt{3}}=-\dfrac{\sqrt{3}}{3}$

<h2>Step-by-step explanation:</h2>

It is given that:

$\cos \theta=-\dfrac{\sqrt{3}}{2}$

where

$\dfrac{\pi}{2}$

i.e. the angle θ lie in the second quadrant.

Also, we know that in the second quadrant sine and cosecant function is positive.

whereas cosine,secant, tangent and cotangent functions are negative.

Now, we know that:

$\cos (\dfrac{5\pi}{6})=-\dfrac{\sqrt{3}}{2}$

i.e. here

$\theta=\dfrac{5\pi}{6}$

Hence, we have:

$\sin (\theta)=\sin (\dfrac{5\pi}{6})\\\\i.e.\\\\\sin \theta=\dfrac{1}{2}$

Also,

$\tan \theta=\dfrac{\sin \theta}{\cos \theta}\\\\i.e.\\\\\tan \theta=\dfrac{\dfrac{1}{2}}{\dfrac{-\sqrt{3}}{2}}\\\\i.e.\\\\\tan \theta=\dfrac{1}{-\sqrt{3}}\\\\i.e.\\\\\tan \theta=-\dfrac{1}{\sqrt{3}}$

Now, on rationalizing we have:

$\tan \theta=-\dfrac{\sqrt{3}}{3}$

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4 years ago

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14b=a then what is a

Varvara68 [4.7K]

$14b=a|\div14\\
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