Answer
You can multiply the first equation by 4 and the second equation by 3.
You can multiply the first equation by 4/3.
You can multiply the first equation by 3.
Explanation
When solving a system of equations by elimination, you want to add or subtract the equations to "get rid" of a variable.
To do that, one of the variables in both equations have to have the same coefficient.
The first answer possible gives x the coefficient of 12 for both equations. You would get 12x+4y=52 and 12x-9y=39. You could subtract those equations to get 13y=13.
The second way gives x the coefficient of 4. You would multiply the first equation by 4/3 to get 4x+4/3y=52/3. You can subtract to get one variable, and then solve from there. Although, multiplying for 4/3 is annoying, so it's not suggested.
You can also "get rid" the the y. Multiply the first equation by 3 to get 9x+3y=39. You can add these equations. When you add 9x+3y=39 and 4x-3y=13 you get 13x=52.
1 + 10 + 18 = (1 + 10) + 18
1 + 10 + 18 = 11 + 18
1 + 10 + 18 = 29
OR
1 + 10 + 18 = 1 + (10 + 18)
1 + 10 + 18 = 1 + 28
1 + 10 + 18 = 29
x=1, y=2
Solve the following system:
{y = 5 - 3 x5 x - 4 y = -3
Substitute y = 5 - 3 x into the second equation:
{y = 5 - 3 x5 x - 4 (5 - 3 x) = -3
5 x - 4 (5 - 3 x) = (12 x - 20) + 5 x = 17 x - 20:{y = 5 - 3 x17 x - 20 = -3
In the second equation, look to solve for x:{y = 5 - 3 x17 x - 20 = -3
Add 20 to both sides:{y = 5 - 3 x17 x = 17
Divide both sides by 17:{y = 5 - 3 xx = 1
Substitute x = 1 into the first equation:{y = 2x = 1
Collect results in alphabetical order:Answer: {x = 1 y = 2
It would stop at 3y+4>11 because the 3y and 4 are unlike terms and can only be divided or multiplied.