Can someone help me with several questions?

Help plz will mark Brainly

irina1246 [14]

Answer:

126 inches

Step-by-step explanation:

If your drawing is on a 1 : 40 scale, to find the scale's height, divide the ride's height by 40.

420 / 40 = 10.5

So the drawing will be 10.5 feet tall.

To convert 10.5 feet to inches, multiply it by 12.

10.5 * 12 = 126 inches

3 0

2 years ago

Write an equation of the line below.

otez555 [7]

Answer:

im not exactly sure but i think it would be y=1x-2

7 0

1 year ago

wanting some extra help with factoring while knowing what method it would be like gcf or grouping etc

Ksju [112]

d) You have a difference of squares:

49y² - 9 = (7y)² - 3²

Recall the identity,

a² - b² = (a - b) (a + b)

So,

49y² - 9 = (7y - 3) (7y + 3)

e) Pull out the common factor 3 from each term:

3x² - 3x - 90 = 3 (x² - x - 30)

Now use the sum-product method. Notice that we can write 30 = 5 • 6, and 5 - 6 = 1, so

3x² - 3x - 90 = 3 (x + 5) (x - 6)

f) Same as in (e), use the sum-product method. Notice that 42 = 7 • 6, and -7 - 6 = -13, so

x² - 13x + 42 = (x - 7) (x - 6)

8 0

1 year ago

Read 2 more answers

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago

Slove for v 8(v-4)+7v=-2

Butoxors [25]

8(v−4)+7v=−2

(8)(v)+(8)(−4)+7v=−2

8v+−32+7v=−2

(8v+7v)+(−32)=−2

15v+−32=−2

15v−32=−2

Add 32 to both sides.

15v−32+32=−2+32

15v=30

Divide both sides by 15.

15v/15=30/15

v = 2

6 0

2 years ago

Read 2 more answers