3r<= 4r - 6
4r - 6 >= 3r
r >= 6
solutions r >= 6
answer
6
7
Answer:
-2
Step-by-step explanation:
do you need an walk through?
and you know what that is.
The solution of the given equation can be all real numbers, except c = 0 and c = 3.
Lets simplify the given problem,
1/c-3 - 1/c = 3/ (c-3)
As the denominators cannot be equal to zero (0) because a division by zero (0) is undefined.
Next, we would multiply both sides of the given by the lowest common multiple (LCM).
The lowest common multiple (LCM) is c(c - 3).
c-[c-3] = 3
c-c+3 = 3
0 = 3-3
0=0
Therefore, the solution of the given equation can be all real numbers, except c = 0 and c = 3.
Learn more about Fractions on:
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