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Alenkinab [10]
3 years ago
8

What should I do I don’t understand

Mathematics
1 answer:
RSB [31]3 years ago
4 0

Answer:

∠MCD and ∠GCM are complementary

∠FGM and ∠MGC are complementary

∠MCD, ∠CDM and ∠DMC add up to 180°

Step-by-step explanation:

Complementary angles are two angles that add up to 90°.

The angles of a triangle add up to 180°

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A system of equations is shown below.
Sedaia [141]

Answer:

6, 0

Step-by-step explanation:

8 0
2 years ago
Someone please tell me how to solve this
rewona [7]
The answer will be 21u^6v^8
6 0
3 years ago
Tom went bowling with $27 to spend.He rented shoes for $5.75 and paid $4.25 for each game.
RideAnS [48]

Answer:

5

Step-by-step explanation:

Subtract the spent money to rent cost:

27-5.75=21.25

Divide the answer to the cost of each game:

21.25/4.25=5

he played 5 times.

6 0
3 years ago
A number cube is rolled 25 times and lands on 2 five times. What is the experimental probability of landing on 2?
olga nikolaevna [1]

Answer:

5/25, 1/5, or 20%

Step-by-step explanation:

Based on the experiment the dice lands on 2 five times, giving you the experimental probability

5 0
1 year ago
Braving blizzard conditions on the planet Hoth, Luke Skywalker sets out at top speed in his snowspeeder for a rebel base 4800 mi
____ [38]

Answer:

v_top = 2400 mi/hr

v_w = 400 mi/h

Step-by-step explanation:

Given:

- Total distance D = 4800 mi

- Headwind journey time taken t_up= 3 hr

- Tailwind journey time taken t_down = 2 hr

Find:

Find the top speed of Luke's snow speeder and the speed of the wind.

Solution:

- The speed of Luke v_l is in stationary frame is given by:

                           v_l = v_w + v_l/w

Where,

           v_w: Wind speed

           v_l/w: Luke speed relative to wind.

- The top speed is attained on his returned journey with tail wind. We will use distance time relationship to calculate as follows:

                         v_top = D / t_down

                         v_top = 4800 / 2

                        v_top = v_down = 2400 mi/hr

- Similarly his speed on his journey up with head wind was v_up:

                         v_up = D / t_up

                         v_up = 4800 / 3

                        v_up = 1600 mi/hr    

- Now use the frame relations to find the wind speed v_w:

                         v_down = v_w + v_l/w

                         v_up = -v_w + v_l/w    

- Solve equations simultaneously:

                         2400 =  v_w + v_l/w

                         1600 =  -v_w + v_l/w

                         4000 = 2*v_l/w

                         v_l/w = 2000 mi/h

                         v_w = 400 mi/h

7 0
3 years ago
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