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3 years ago

8

What should I do I don’t understand

1 answer:

RSB [31]3 years ago

4 0

Answer:

∠MCD and ∠GCM are complementary

∠FGM and ∠MGC are complementary

∠MCD, ∠CDM and ∠DMC add up to 180°

Step-by-step explanation:

Complementary angles are two angles that add up to 90°.

The angles of a triangle add up to 180°

You might be interested in

Out of 1200 students of a school only 85% passed. how many students failed?

DerKrebs [107]

Answer:15

Step-by-step explanation:

If 85% pass then 15% failed and 15% of 1,200 is 180 so 180 people failed.

7 0

3 years ago

Anon25 [30]

The middle point of BC is (0,2), the midpoint of CD is (1,0)
to prove two lines are parallel, prove their slopes are the same.
slope of BD: m=rise/run=4/-2=-2 (the run is negative because to get to B from D on the grid, you have to move from right to left, then upward. If the horizontal move is from left to right, the run is positive)
slope of EG: m=rise/run=2/-1=-2
EG and BD have the same slope, so they are parallel.

3 0

3 years ago

valentinak56 [21]

Answer: B

Step-by-step explanation:

The maximum is 100 and the minimum is 27.

The only option that shows this is B.

3 0

1 year ago

Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118. If a recent test-taker

LuckyWell [14K]

Answer:

Probability that the student scored between 455 and 573 on the exam is 0.38292.

Step-by-step explanation:

We are given that Math scores on the SAT exam are normally distributed with a mean of 514 and a standard deviation of 118.

<u><em>Let X = Math scores on the SAT exam</em></u>

So, X ~ Normal( $\mu=514,\sigma^{2} =118^{2}$ )

The z score probability distribution for normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean score = 514

$\sigma$ = standard deviation = 118

Now, the probability that the student scored between 455 and 573 on the exam is given by = P(455 < X < 573)

P(455 < X < 573) = P(X < 573) - P(X $\leq$ 455)

P(X < 573) = P( $\frac{X-\mu}{\sigma}$ < $\frac{573-514}{118}$ ) = P(Z < 0.50) = 0.69146

P(X $\leq$ 2.9) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{455-514}{118}$ ) = P(Z $\leq$ -0.50) = 1 - P(Z < 0.50)

= 1 - 0.69146 = 0.30854

<em>The above probability is calculated by looking at the value of x = 0.50 in the z table which has an area of 0.69146.</em>

Therefore, P(455 < X < 573) = 0.69146 - 0.30854 = <u>0.38292</u>

Hence, probability that the student scored between 455 and 573 on the exam is 0.38292.

7 0

3 years ago

Ratling [72]

Step-by-step explanation:

1. 1*1/6= 1 /6=1.67

2. 9*7/10= 63/10= 6.3

3. 7*4/8= 28/8= 3.5

4. 1/2 of 2= 1/2*2= 0.5*2= 1

5. 1/12 of 2= 1/12*2= 8.33*2= 16.66

6.2/6 of 2= 2/6*2= 3.33*2= 6.66

7. 1/3 of 5= 1/3*5= 3.33*5= 16.65

8. 3/10 of 8= 3/10*8= 0.3*8= 2.4

Hope it's help you ♥️

7 0

2 years ago