Interesting question about feet and inches. The best way to solve this problem is to ask yourself how many inches are in a foot. Since there are 12 inches in every foot then the length of 2'8" can be written as (2*12)" + 8". Which is 24+8 or 32 inches. The second number (1'6") can be written as (1*12)"+6" which is 18 inches. 32 + 18 = 50 inches. Or, if you want to change this back into feet and inches just divide it by 12. 50/12 is 4 R. 2. So 4'2".
1. The answer would be (D). This is because you will plug is the (x) of the ordered pair into the equation(y=-2x), so first off would be (y=-2(-2)). since your multiplying a negative time a negative, you will get your (y) which is 4. Now you do this with the rest. -2(1)=-2 and -2(3)=-6.
2. This would be (A). This answer is simple. First you will take one of the equations (y=-x-1) and plug x into it's place so, y=-3-1, getting your answer(y) as being -4. Now you do the same with the other pair. y=-5-1, getting -6, showing (A) as your answer.
3.The answer will be (A)y is 2 times x. this is because you wou would make out the equation from the answer (y=2x). Now knowing your equation, all thats left is plugging in your (x) factors. so y=2(1), getting your (y) value of 2 and you would do this with the rest of your x factors.
4. y=5+x
y=5+(2)= 7
y=5+(3)= 8
y=5+(4)= 9
5. (B)y is 3 times x
y=3(x)
y=3(3)=9
y=3(4)=12
y=3(5)=15
6. (C)y is 6 less than x
y=6-(x)
y=6-(8)=2
y=6-(9)=3
y=6-(10)=4
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean 
and standard deviation 
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:
Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:
Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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U will take the two diagrams
And name them A N B
U then solve the triangle by triangle
