Question

Emma measured a line to be 16 inches long. If the actual length of the line is 15.3 inches, then what was the percent error of the measurement, to the nearest tenth of a percent?

Answer 1

Answer:

4.6% (nearest tenth)

Step-by-step explanation:

percent error = (|approx - actual| ÷ actual) × 100

percent error = (|16 - 15.3| ÷ 15.3) × 100

                      = 4.6% (nearest tenth)

Answer 2

$\sf\% \: error = \frac{ |approx - actual| }{actual} \times 100$

• Approx = 16
• Actual = 15.3

$\tt\% \: error = \frac{ |16 - 15.3| }{15.3} \times 100$

$\tt\% \: error = \frac{ |0.7| }{15.3} \times 100$

$\tt\% \: error = \frac{ |0.7| }{ \frac{153}{10} } \times 100$

$\tt\% \: error = \frac{0.7}{ \frac{153}{10} } \times 100$

$\tt\% \: error = \frac{ \frac{7}{10} }{ \frac{153}{10} } \times 100$

$\tt\% \: error = \frac{7 }{ 153 } \times 100$

$\tt\% \: error = \frac{7 00}{ 153 }$

$\tt\% \: error =4.57\%$

• Thus, The % error is 4.6% when rounded off to the nearest tenth!!~