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3 years ago

15

Delia spent 45 minutes working on her book report. She finished the report at 6:10 p.m. at what time did Delia start working on

her report

2 answers:

inna [77]3 years ago

7 0

All you have to do is subtract 45 from 6:10. Which is 5:65pm she started

Dmitry [639]3 years ago

4 0

5:25

just act like the time is 6:00 then minus 45 and add 10 to your answer.

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After solving $\sqrt[5]{128x^8y^2}$ we get $2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}$

Step-by-step explanation:

We need to solve $\sqrt[5]{128x^8y^2}$

Applying the rule: $\sqrt[a]{xy}=\sqrt[a]{x}.\sqrt[a]{y}$

$\sqrt[5]{128x^8y^2}\\=\sqrt[5]{128}\sqrt[5]{x^8}\sqrt[5]{y^2}\\We\,\,know\,\,that\,\,128=2\times2\times2\times2\times2\times2\times2=2^7\,\,or\,\,2^5.2^2\\=\sqrt[5]{2^5.2^2}\sqrt[5]{x^5.x^3}\sqrt[5]{y^2}\\=(2^5)^{\frac{1}{5}}\sqrt[5]{2^2}\sqrt[5]{x^5}\sqrt[5]{x^3}\sqrt[5]{y^2}\\=2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}$

So, After solving $\sqrt[5]{128x^8y^2}$ we get $2x\sqrt[5]{4}\sqrt[5]{x^3}\sqrt[5]{y^2}$

Keywords: Solving with Exponents

Learn more about Solving with Exponents at:

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