y=2X-5 and 4X-Y=7
Putting the value of Y in 2nd equation:
4x-2x+5=7
2x=7-5
2x=2
OR,x=2/2=1
putting the value of x in equation 1:
y=2x-5
y=2*1-5
y=2-5
y=-3
The center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
<h3>Equation of a circle</h3>
The standard equation of a circle is expressed as:
x^2 + y^2 + 2gx + 2fy + c = 0
where:
(-g, -f) is the centre of the circle
Given the equations
x^2 +y^2 – 12x – 2y +12 = 0
Compare
2gx = -12x
g = -6
Simiarly
-2y = 2fy
f = -1
Centre = (6, 1)
Hence the center of a circle whose equation is x^2 +y^2 – 12x – 2y +12 = 0 is (6,1)
Learn more on equation of a circle here: brainly.com/question/1506955
Answer:
-3/4
Step-by-step explanation:
rise is three run is four
When given a system of equations, the "solutions" are defined where two equations intersect, or meet.
A. The point where the lines p(x) and g(x) meet is (3, -1), and thus this is considered the solution set.
B. Because there are three lines in total, g(x) is able to intersect both lines one time, and so it has two pairs of solutions.
The first is (3, -1), which has already been established with p(x).
The second is (0, 5), and this is where it intersects with f(x).
C. The solution to f(x) = g(x) is 0, as this is the only x value where both equations are equal.
Hope my answer helped!
2/4 esa es una ojalá y pude contestar a tiempo
