3 years ago

URGENT I NEED HELPSKSNDND

Mathematics

1 answer:

JulsSmile [24]3 years ago

7 0

Answer:

I plotted and Vehicle A is traveling faster.

Step-by-step explanation:

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PLEASE DO THIS FOR ME, The populations of six countries are listed in this chart. Add one more country of your choosing and add

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Answer:

There is no answer laugh out loud

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3 years ago

Jen has 2 meters of taffy. She wants to give each of her 3 best friends an equal amount of taffy. How many centimeters of taffy

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Find the values of x and y that satisfy the equation.<br><br> 3x+6i=27+yi<br> x

Misha Larkins [42]

Answer:

x = 9

y = 6

Step-by-step explanation:

3x+6i=27+yi

The real components have to be equal and the imaginary components have to be equal

3x = 27

divide by 3

3x/3 = 27/3

x=9

6i = yi

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4 years ago

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A restaurant purchased kitchen equipment on January 1, 2017. On January 1, 2019, the value of the equipment was $14 comma 550

timama [110]

Answer:

$\frac{dV(t)}{dt} =$ - 1675.38

Step-by-step explanation:

In 2017, the vakue of the kitchen equipment was $14550

V(0)=$14550

Its value after then was modelled by $V(t)=14550e^{-0.158t$

We are required to find the rate of change in value on January 1, 2019

$V(t)=14550e^{-0.158t$

$\frac{dV(t)}{dt} =\frac{d}{dt}14550e^{-0.158t$

$\frac{dV(t)}{dt} =14550 \frac{d}{dt}e^{-0.158t$

$\\Let u= -0.158t,\frac{du}{dt}=-0.158$

$\frac{dV(t)}{dt} =14550 \frac{d}{du}e^u\frac{du}{dt}$

$\frac{dV(t)}{dt} =14550 X -0.158 e^{-0.158t}=-2298.9e^{-0.158t}$

In 2019, i.e. 2 years after, t=2

The rate of change of the value

$\frac{dV(t)}{dt} =-2298.9e^{-0.158X2}$

= $\frac{dV(t)}{dt} =-2298.9e^{-0.316}$ = - 1675.38

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3 years ago

Does anyone know the answer please help!!

Reil [10]

B) Hexagon

hope you got it right

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4 years ago