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3 years ago

Are you good at math then here

Mathematics

1 answer:

Nikolay [14]3 years ago

7 0

Answer:

see below

Step-by-step explanation:

The term -2t suggests that there are "t" of something that costs $2, or there are 2 of something that costs "t" dollars. The options marked include both interpretations.

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Determine if the statement is always, sometimes or never true. The measure of an exterior angle at the vertex of a polygon equal

jeka94

Answer:

I believe it is never

Step-by-step explanation:

Sorry if I'm wrong ...

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3 years ago

Please help me due tomorrow

EastWind [94]

Answer:

B. y=6x+9

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-3-3)/(-2+1)= (-6)/(-1)= 6

m=6

y=mx+b y=6x+b

plug in one of the points for b

-3=6(-2)+b -3=-12+b -3+12= 9

y=6x+9

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3 years ago

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I just don’t understand the math

olchik [2.2K]

I believe the answer is 6

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3 years ago

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A ball is thrown upward with an initial velocity of 60 mph. it is thrown from a height of 5 feet. what is the maximum height it

natima [27]

Answer:

h = 61.25 m

Step-by-step explanation:

It is given that,

The initial velocity of the ball, v = 60 m/s

It is thrown from a height of 5 feet, $h_o=5\ ft$

We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

$h=-16t^2+vt+h_0$

Putting all the values,

$h=-16t^2+60t+5$ .....(1)

For maximum height, put

$\dfrac{dh}{dt}=0\\\\\dfrac{-16t^2+60t+5}{dt}=0\\\\-32t+60=0\\\\t=\dfrac{-60}{-32}\\\\t=1.875\ s$

Put t = 1.875 in equation (1)

$h=-16(1.875)^2+60(1.875)+5\\\\h=61.25\ m$

So, the maximum height reached by the ball is 61.25 m.

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3 years ago

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soldi70 [24.7K]

X=11 because u Solve for the first variable in one of the equations, then substitute the result into the other equation.

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3 years ago

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