Answer:
Option b is the correct answer as both the equations are true for given solution.
Step-by-step explanation:
Given equations are:
-0.1x-0.3y=1.2
0.2x-0.5y=2
We can observe each graph and find the point that is the solution and put the point in the equations to know if that point is the solution
<u>For option A:</u>
(0,4)
Putting x=0 and y = 4 in both equations
This is not the correct answer as both equations are not true with this solution
<u>For Option B:</u>
(0,-4)
Putting x = 0 and y = -4 in both equations
Both equations are true for (0,-4) hence it is the solution of the system.
<u>For Option C:</u>
(4,0)
Not true for both equations
Hence,
Option b is the correct answer.
Answer:
2
Step-by-step explanation:
this is a 30-60-90 Δ and the ratio of the sides are 1 : : 2
1 / 2 = / x
cross-multiply: x = 2
Answer:
Step-by-step explanation:
You have the equation .
Then, to solve for the variable from the equation you need:
Make the subtraction of the right side of the equation:
(As the denominators are 1 and , the least common denominator is )
Multiply to both sides:
Add to both sides:
And finally divide both sides by :
So the first one, 1.2 >11/5. and the second one 1/3> 1/2
Complete question :
It is estimated 28% of all adults in United States invest in stocks and that 85% of U.S. adults have investments in fixed income instruments (savings accounts, bonds, etc.). It is also estimated that 26% of U.S. adults have investments in both stocks and fixed income instruments. (a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places. (b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?
Answer:
0.929 ; 0.306
Step-by-step explanation:
Using the information:
P(stock) = P(s) = 28% = 0.28
P(fixed income) = P(f) = 0.85
P(stock and fixed income) = p(SnF) = 26%
a) What is the probability that a randomly chosen stock investor also invests in fixed income instruments? Round your answer to decimal places.
P(F|S) = p(FnS) / p(s)
= 0.26 / 0.28
= 0.9285
= 0.929
(b) What is the probability that a randomly chosen U.S. adult invests in stocks, given that s/he invests in fixed income instruments?
P(s|f) = p(SnF) / p(f)
P(S|F) = 0.26 / 0.85 = 0.3058823
P(S¦F) = 0.306 (to 3 decimal places)