Question

A customer ordered fourteen zingers. zingers are placed in packages of​ four, three, or one. in how many different ways can this order be​ filled?

Answer 1

fourteen zingers. zingers are placed in packages of four, three, or one

4*3=12

1*2=2

4*2=8

3*2=6

4*2=8

1*6=6

4*2=8

3*1=3

1*3=3

4*1=4

3*3=9

1*1=1

4*1=4

3*2=6

1*4=4

4*1=4

3*1=3

1*7=7

4*1=4

1*10=10

3*4=12

1*2=2

3*3=9

1*5=5

3*2=6

1*8=8

3*1=3

1*11=11

1*14=14

13 ways

Answer 2

Answer:

The number of different ways this order can be filled is:

                              13 ways.

Step-by-step explanation:

A customer ordered fourteen zingers.

zingers are placed in packages of​ four, three, or one.

Case-1

If the number of packages of four are: 3

Then 4×3=12 zingers.

a)

So, there will be zero packet of 3.

and 2 packs of 1.

Since, 12+2×1=14

Case-2

If the number of packages of four are: 2

i.e. 4×2= 8 zingers.

a)

If number of packages of 3 are: 2

i.e. 3×2=6

then number of package of 1 have to be 0.

b)

If number of packages of 3 are: 1

i.e. 3×1=3 zingers

Number of packages of 1 zinger will be: 3

i.e. 8+3+3=14

c)

If number of packages of 3 are: 0

Then number of packets of 1 will be:  6

Case-3

If the number of packages of four are: 1

a)

If number of packages of 3 are: 3

i.e. 3×3=9 zingers.

Hence, number of packets of 1 have to be: 1

b)

If number of packages of 3 are: 2

i.e. 3×2=6 zingers

Then number of packets of 1 have to be: 4

c)

If number of packages of 3 are: 1

i.e. 3×1=3 zingers

Then number of packets of 1 have to be: 7

d)

If number of packages of 3 are: 0

i.e. 3×0=0 zingers

Then number of packets of 1 have to be: 10

Case-4

If the number of packages of four are: 0

a)

If number of packages of 3 are: 4

i.e. 3×4=12 zingers

Then number of packets of 1 have to be: 2

b)

If number of packages of 3 are: 3

i.e. 3×3=9 zingers

Then number of packets of 1 have to be: 5

c)

If number of packages of 3 are: 2

i.e. 3×2=6 zingers

Then number of packets of 1 have to be: 8

d)

If number of packages of 3 are: 1

i.e. 3×1=3 zingers

Then number of packets of 1 have to be: 11

e)

If number of packages of 3 are: 0

i.e. 3×0=0 zingers

Then number of packets of 1 have to be: 14

There are total 13 ways of doing so.

( 1 from case-1

3 from case-2

4 from case-3

and 5 from case-4

i.e.  1+3+4+5=13 ways )