Values of the composite function:
![(g\cdot f)(-1)=6](https://tex.z-dn.net/?f=%28g%5Ccdot%20f%29%28-1%29%3D6)
![(g\cdot f)(0)=7](https://tex.z-dn.net/?f=%28g%5Ccdot%20f%29%280%29%3D7)
![(f\cdot g)(-1)=3](https://tex.z-dn.net/?f=%28f%5Ccdot%20g%29%28-1%29%3D3)
![(f\cdot g)(4)=2](https://tex.z-dn.net/?f=%28f%5Ccdot%20g%29%284%29%3D2)
Step-by-step explanation:
Given two functions f(x) and g(x), their composite function is given by
![(f\cdot g)(x) = f(g(x))](https://tex.z-dn.net/?f=%28f%5Ccdot%20g%29%28x%29%20%3D%20f%28g%28x%29%29)
Which means using the output value of g(x) as input for f(x).
Let's start by computing
![(g\cdot f)(-1)](https://tex.z-dn.net/?f=%28g%5Ccdot%20f%29%28-1%29)
First, we compute the value of f(-1), which is (from the graph)
f(-1) = 1
Now we use this value as input into g(x); we notice that at x = 1, the value of g(x) is 6, therefore:
![(g\cdot f)(-1)=6](https://tex.z-dn.net/?f=%28g%5Ccdot%20f%29%28-1%29%3D6)
Now we evaluate
![(g\cdot f)(0)](https://tex.z-dn.net/?f=%28g%5Ccdot%20f%29%280%29)
First, we compute the value of f(0), which is (from the graph)
f(0) = 0
Now we use this value as input into g(x); at x = 0, the value of g(x) is 7, therefore:
![(g\cdot f)(0)=7](https://tex.z-dn.net/?f=%28g%5Ccdot%20f%29%280%29%3D7)
Now we evaluate
![(f\cdot g)(-1)](https://tex.z-dn.net/?f=%28f%5Ccdot%20g%29%28-1%29)
First, we compute the value of g(-1), which is (from the graph)
g(-1) = 5
Now we use this value as input into f(x); at x = 5, the value of f(x) is 3, therefore:
![(f\cdot g)(-1)=3](https://tex.z-dn.net/?f=%28f%5Ccdot%20g%29%28-1%29%3D3)
Finally we evaluate
![(f\cdot g)(4)](https://tex.z-dn.net/?f=%28f%5Ccdot%20g%29%284%29)
First, we compute the value of g(4), which is (from the graph)
g(4) = 4
Now we use this value as input into f(x); at x = 4, the value of f(x) is 2, therefore:
![(f\cdot g)(4)=2](https://tex.z-dn.net/?f=%28f%5Ccdot%20g%29%284%29%3D2)
Learn more about composite functions:
brainly.com/question/2723982
brainly.com/question/2456302
brainly.com/question/1949601
brainly.com/question/1900154
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