Answer:
Step 1 (IM AM NOT SURE NOT MY FAULT IF ITS WRONG)
Step-by-step explanation:
Answer:
The correct option is;
d(t) = 6·cos(π/3·t) + 28
Step-by-step explanation:
The general form of a cosine function is given as follows;
y = A·cos(B·x - C) + D
Where;
A = The amplitude = The distance from the peak to the midline = 1/2×(Maximum - minimum)
The amplitude = 1/2 × (34 - 22) = 6 inches
B = 2·π/P = 2·π/6 = π/3
P = The period = 6 seconds
C/B = The phase shift
D = The midline = Minimum + Amplitude = 22 + 6 = 28 inches
x = The independent variable
Therefore, to model the function of the wave can be given as follows;
d(t) = 6·cos(π/3·t) + 28
I = P x R x T
I = 6000 x .04 x 2
I = $480
He will be paid $480 interest in the first two years
Answer:
x = 11°
Step-by-step explanation:
The parallel lines suggest we look to the relationships involving angles and transversals. The angle marked 33° and ∠CAB are alternate interior angles, hence congruent:
∠CAB = 33°
5x is the measure of the external angle opposite that internal angle and angle 2x of ΔABC, so it is equal to their sum:
5x = 2x + 33°
3x = 33° . . . . . . . . . subtract 2x
x = 11° . . . . . . . . . . . divide by 3
(m - 3)(m + 5)= 0
m= {3, -5}