Answer:
3. x+8
4. 6y
5. 1/2m
6. 50/h
7. 7-n
8. 15+x
9. 2t/12
10. p² -3
11. 2k-7
12. 3(w+5)
13. C
14. The error was it was written that you would subtract the pages read by pages in the article which is incorrect. You would subtract pages total (5) by pages read (p). So it is 5-p.
15. 4v
16. 16/p
17. 2.97/p
18. 20+j
19. 7-d
20. m/60
21. y/12
22. unit rate-8
23. unit rate-1.5
24. unit rate-2.4
25. unit rate-6.8
26. C
Answer:
Step-by-step explanation:
A scalar is a constant value that is multiplied throughout a matrix.
e.g.
In number 1 the set up would look like this
3 * ![\left[\begin{array}{ccc}3&-1&5\\2&1&-4\\-6&3&2\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%26-1%265%5C%5C2%261%26-4%5C%5C-6%263%262%5Cend%7Barray%7D%5Cright%5D)
To solve this, you must distribute the 3 to each value within the matrix
The solution to #1 would be
M = ![\left[\begin{array}{ccc}9&-3&15\\6&3&-12\\-18&9&6\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D9%26-3%2615%5C%5C6%263%26-12%5C%5C-18%269%266%5Cend%7Barray%7D%5Cright%5D)
So we can start with the full of possibilities and eliminate them one by one.
The full set is {0,1,2,3,4,5,6,7,8,9}.
Now we know that any prime greater than 2 is odd as otherwise it would have 2 as a factor, so we can eliminate all of these digits that would be an even number, leaving:
{1,3,5,7,9}
We also know that any prime greater than 5 cannot be a multiple of 5 and that all numbers with 5 in the digits are a multiple of 5, so we can eliminate 5.
{1,3,7,9}
We know that 11,13,17 and 19 are all primes, so we cannot eliminate any more of these, leaving the set:
{1,3,7,9} as our answer.
Answer:
I do believe that the answer would be 56%
Step-by-step explanation:
Using estimation if the box is half full it would have 4.5 books in the box, if you add that extra book it would be around 56%
