3 years ago

1-22 teacher was no help

Mathematics

1 answer:

damaskus [11]3 years ago

3 0

1) 1,2,3,4,5,6,7
2) -3,-2,-1,0,1,2,3,4,5,6,7
3)-3,-2,-1
4)1,2,3,4

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$T = (1, 8)$

$E =(3, 8)$

$X =(6, 2)$

$A=(3, 2)$

$S = (1, 4)$

The area of the pentagon is then calculated using:

$Area = \frac 12|(x_1y_2+x_2y_3+x_3y_4+x_4y_5+x_5y_1) -(y_1x_2+y_2x_3+y_3x_4+y_4x_5+y_5x_1)|$

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$Area = \frac 12|(1 \times 8 +3 \times 2+6\times2+3 \times 4 + 1 \times 8) -(8\times3+8\times6+2\times3+2\times1+4\times1)|$

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$Area = \frac 12|46 -84|$

$Area = \frac 12|-38|$

Remove absolute bracket

$Area = \frac 12 \times 38$

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