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fredd [130]
3 years ago
9

Prove that the altitude to the base of an isosceles triangle is also the angle bisector of the angle from which it is drawn

Mathematics
1 answer:
andriy [413]3 years ago
5 0

Step-by-step explanation:

To prove- Altitude to the base of an isosceles triangle bisects the angle from which it is drawn.

In the given figure ΔABC (isosceles triangle) whose sides AB=AC

From ∠A an altitude is drawn to base (BC) which meets BC at X

∠AXB=90 and ∠AXC =90

∴We need to prove ΔXAB= ΔXAC for altitude to bisect the ∠ BAC

In Δ AXB and Δ AXC

AB=AC (same hypotenuse)

AX= common altitude (serve as the common leg of the hypotenuse)

ΔAXB ≅ ΔAXC

Hence, we can conclude that the corresponding angle∠ XAB = ∠XAC. QED

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Obtain the general solution to the equation. (x^2+10) + xy = 4x=0 The general solution is y(x) = ignoring lost solutions, if any
alukav5142 [94]

Answer:

y(x)=4+\frac{C}{\sqrt{x^2+10}}

Step-by-step explanation:

We are given that a differential equation

(x^2+10)y'+xy-4x=0

We have to find the general solution of given differential equation

y'+\frac{x}{x^2+10}y-\frac{4x}{x^2+10}=0

y'+\frac{x}{x^2+10}y=4\frac{x}{x^2+10}

Compare with

y'+P(x) y=Q(x)

We get

P(x)=\frac{x}{x^2+10}

Q(x)=\frac{4x}{x^2+10}

I.F=e^{\int\frac{x}{x^2+10} dx}=e^{\frac{1}{2}ln(x^2+10)}

e^{ln\sqrt(x^2+10)}=\sqrt{x^2+10}

y\cdot \sqrt{x^2+10}=\int \frac{4x}{x^2+10}\times \sqrt{x^2+10} dx+C

y\cdot \sqrt{x^2+10}=\int \frac{4x}{\sqrt{x^2+10}}+C

y\cdot \sqrt{x^2+10}=4\sqrt{x^2+10}+C

y(x)=4+\frac{C}{\sqrt{x^2+10}}

6 0
3 years ago
If all city buses carry the same number of passengers, what is the least number of buses needed to carry 710 passengers? 5 10 11
noname [10]

The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

<h3>What is the least number of buses needed to carry 710 passengers? </h3>

Given that;

  • Number of passengers n = 710
  • Least number of buses need B = ?

To get the least number of buses, we say;

Number of buses B = 710 ÷ 150

Number of buses B = 4.7 ≈ 5

The least number of buses needed to carry 710 passengers is 5.

Option A)5 is the correct answer.

Learn to solve more word problems here: brainly.com/question/2610134

#SPJ4

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1 year ago
Please help&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;&gt;
Annette [7]

Answer:

The answer is B, -5 is a rational number and integer! :)

Step-by-step explanation:

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