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3 years ago

Find the width of a rectangle with perimeter 92 and length 19

Mathematics

2 answers:

lora16 [44]3 years ago

3 0

Answer:

Step-by-step explanation:

perimeter = l + b + l + b or 2(l + b)

92 = 19 + 19 + 2b

92 = 38 + 2b

2b = 92 - 38

2b = 54

b = 54 / 2

b = 27

breadth or width of the triangle = 27

length = 19

Juliette [100K]3 years ago

3 0

Answer:

Width of the rectangle is 27

Step-by-step explanation:

Given:

$Perimeter= 92 units\\\\Length= 19 units$

Perimeter of the rectangle = $2(Length+Width)$

Putting the values:

$92=2(19+Width)$

Dividing by '2' both the sides:

$92/2=19+width$

$46=19+Width$

Subtracting '19' both the sides:

$46-19=Width$

$Width=27 units$

The width of the rectangle is 27 units with Length=19 units and Perimeter= 92 units

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