Answer:
1) These linear functions must not describe a pair of parallel lines.
2) Any intersection of two lines determines a point.
Step-by-step explanation:
Hi there!
Well, since no further details were given. Let's call the linear function that represents the number of animals adopted from the shelter
. And
the hours the volunteers work at the shelter each week ![v(x)](https://tex.z-dn.net/?f=v%28x%29)
1) These linear functions must not describe a pair of parallel lines.
If these lines intersect, then their slope must be different.
![m_{s}\neq m_{v}\\e.g.\\m_{s}=2\\m_{v}=-2](https://tex.z-dn.net/?f=m_%7Bs%7D%5Cneq%20m_%7Bv%7D%5C%5Ce.g.%5C%5Cm_%7Bs%7D%3D2%5C%5Cm_%7Bv%7D%3D-2)
Equal slopes, parallel lines. Parallel lines, no intersection.
Different slopes, then there is an intersection at some point.
2) Any intersection of two lines determines a point. Let's find it.
So to find one common point equalize the two functions, then find the value for the x-coordinate. Plug it in one of the functions, e.g.
![2x+2=-2x+2 \rightarrow 4x=0 \therefore x=0\\2(0)+2=2 \Rightarrow (0,2)](https://tex.z-dn.net/?f=2x%2B2%3D-2x%2B2%20%5Crightarrow%204x%3D0%20%5Ctherefore%20x%3D0%5C%5C2%280%29%2B2%3D2%20%5CRightarrow%20%280%2C2%29)
At the common point, both functions after inserted the same value in the Domain (x) return the same result for their respective Range set.