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Ilya [14]
3 years ago
11

solve the proportion. the quantity 13 minus b end of quantity divided by 6 equals the quantity 2 minus 0.5 multiplied by b end o

f quantity divided by 4. a. 40 b. 32 c. 64 d. 72
Mathematics
1 answer:
tatyana61 [14]3 years ago
5 0
\frac{13-b}{6}= \frac{2-0.5b}{4} \\ 4(13-b)=6(2-0.5b) \\ 52-4b=12-3b \\ b=40
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4 0
2 years ago
a container holds 15 pennies 8 nickels and 10 dimes you will randomly select two coins without replacement what is the probabili
AlexFokin [52]
<span>A container holds 15 pennies, 8 nickels, and 10 dimes. 
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3 0
3 years ago
* NOTICE THIS IS A 2 PART QUESTION
blondinia [14]

Answer: you would have to purchase $1300 of merchandise and the total yearly amount paid to the warehouse for each plan is $1210

Step-by-step explanation:

Let x represent the number of dollars of merchandise that you would have to purchase in a year to pay the same amount under both plans.

Plan A offers an annual membership fee of $300 and you pay 70%, of the manufacturers reccomended list price. This means that the total cost of using plan A would be

300 + 0.7x

Plan B offers an annual membership fee of $40 and you pay 90% of the manufacturers reccomended list price.

This means that the total cost of using plan B would be

40 + 0.9x

For both plans to be the same,

300 + 0.7x = 40 + 0.9x

0.9x - 0.7x = 300 - 40

0.2x = 260

x = $1300

The total yearly amount paid to the warehouse for each plan would be

40 + 0.9 × 1300 = $1210

6 0
3 years ago
What number best completes both equations? 5/7÷1/3=? ?×1/3=5/7
Nat2105 [25]

Consider the given equations:

The first equation is as:

\frac{5}{7} \div \frac{1}{3} = ?

So, \frac{5}{7} \div \frac{1}{3}

= \frac{5}{7} \times \frac{3}{1}

Multiplying the given fractions, we get as

= \frac{15}{7}

Now, consider the second equation as:

? \times \frac{1}{3} = \frac{5}{7}

Multiplying by '3' to both the sides of the equation, we get

? \times \frac{1}{3} \times 3 = 3 \times \frac{5}{7}

? = \frac{15}{7}

So, the number which best completes both the equations is \frac{15}{7}.

6 0
3 years ago
What is the area of a triangle whose vertices are D(3,3), E(3,-1), and F(-2,-5)?
Elis [28]

There is a formula which employs the use of determinants and which helps us calculate the area of a triangle if the vertices are given as (x_1,y_1),(x_2,y_2),(x_3,y_3). The formula is as shown below:

Area=\frac{1}{2}\begin{vmatrix}x_1&y_1&1 \\ x_2&y_2&1\\ x_3&y_3&1\end{vmatrix}

Now, in our case, we have: (x_1,y_1)=(3,3)

(x_2,y_2)=(3,-1), and

(x_3,y_3)=(-2,-5)

Thus, the area in this case will become:


Area=\frac{1}{2}\begin{vmatrix}3&3&1 \\ 3&-1&1\\ -2&-5&1\end{vmatrix}

Therefore, Area=\frac{1}{2}\times [[3(-1\times 1-(-5)\times 1]-3[3\times 1-(-2)\times 1]+1[3\times -5-2]]= \frac{1}{2}\times -20=-10

We know that area cannot be negative, so the area of the given triangle is <u>10 squared units</u>.



3 0
3 years ago
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