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3 years ago

A road crew spread 1 1/3 tons of gravel evenly over 8 feet of road.how many tons of gravel did they spread on each foot of road?

1 answer:

3 0

$\bf 1\frac{1}{3}\div 8\implies \cfrac{1\frac{1}{3}}{8}\implies \cfrac{\frac{1\cdot 3+1}{3}}{\frac{8}{1}}\implies \cfrac{\frac{4}{3}}{\frac{8}{1}}\implies \cfrac{4}{3}\cdot \cfrac{1}{8}\implies \cfrac{4}{24}\implies \cfrac{1}{6}$

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cestrela7 [59]

Answer:

Outliers are sample values that lie very far away from the majority of the other sample values. Centers Distributions Outliers Frequencies are sample values that lie very far away from the majority of the other sample values.

Step-by-step explanation:

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3 years ago

What is the slope of the line that passes through the points (4, 10)(4,10) and (1, 10) ?(1,10)? Write your answer in simplest fo

ikadub [295]

Answer:

Step-by-step explanation:

Slope = Δy/Δx

Slope = 10-10/4-1

Slope = 0/3

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2 years ago

Pre-calc, Review the table of values for function h(x). (image attached)

GalinKa [24]

Answer:

$\lim_{x \to 10^+} h(x) = 18.5$

Step-by-step explanation:

As x approaches 10 from the right side, h(x) approaches 18.5 but never touches it.

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3 years ago

Use the midpoint formula to estimate the sales of Cars, Inc. in 2009, given the sales in 2008 and 2010. Assume that the sales of

lana [24]

Answer:

<em>The estimated sales were $260 million</em>

Step-by-step explanation:

Assume the endpoints of a segment are (x1,y1) and (x2,y2).

The midpoint (xm,ym) is calculated as follows:

$\displaystyle x_m=\frac{x_1+x_2}{2}$

$\displaystyle y_m=\frac{y_1+y_2}{2}$

The sales ov Cars, Inc. were (2008,240 million) and (2010,280 million). We need to use the midpoint to estimate the sales in 2009:

$\displaystyle x_m=\frac{2008+2010}{2}=2009$

$\displaystyle y_m=\frac{240+280}{2}=260$

The estimated sales were $260 million

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2 years ago

s344n2d4d5 [400]

Answer:

D.) 8:00

It’s a geometric problem so when plugged in you get answer D

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2 years ago