The fare of $(20 - 2.5) = $17.5 will maximize the total fare.
<h3>What is Differentiation?</h3>
Differentiation means the rate of change of one quantity with respect to another. The speed is calculated as the rate of change of distance with respect to time.
Here, The operator for a round-trip fare of $20, carries an average of 500 people per day.
It is estimated that 20 fewer people will take the trip, for each $1 increase in fare.
for $x increase in fare, 20x less people will take the trip and at that time the total fare F is given by
f(x) =(20 + x)(500 - 20x)
f (x) = 10000 + 100x - 20x²
For f(x) to be maximum, the condition is dy/dx = 0
100 - 40x = 0
⇒ x = 2.5
Thus, the fare of $(20 - 2.5) = $17.5 will maximize the total fare.
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Answer:
Hey!
Your answer is 
!
Step-by-step explanation:
Also can be written as 41/8!
HOPE THIS HELPED!
Answer:
92.31 km
Step-by-step explanation:
Combined speed = 50+80
= 130 km/hour
Time = 100/130 = 10/13 hours to collide
Speed × time = distance
distance = 10/13 × 120
= 92.30769231 km
Step-by-step explanation:
f(3)=?
f(x)=2x+5
put x=3,
f(3)=2(3)+5=6+5=11
------------
g(2)=?
g(x)=x^2-3
put x=2,
g(2)=2^2-3=4-3=1
-----------------
g(f(-1))=?
g(x)=x^2-3
and f(-1)=2(-1)+5= -2+5=3
so g(f(-1))=3^2-3=9-3=6
----------------
f(g(-1))=?
f(x)=2x+5
g(x)=g(-1)=(-1)^2-3=1-3= -2
f(g(-1))=2(-2)+5= -4+5=1
----------------
g(f(x))=?
g(x)= x^2-3
put x=f(x),
g(f(x))=f(x)^2-3=(2x+5)^2-3=4x+25+20x-3=24x+25
Daniel spent $4.75 for a lunch and $1.85 for a snack
$4.75+$1.85=$6.6, so Daniel spent $6.6 total
Kyle spent $5.75 for lunch and $1.00 for a snack
$5.75+$1.00=$6.75, so Kyle spend total $6.75.
Final step:
$6.75-$6.6=$0.15. As a result, Kyle spent $0.15 or 15 cent more than Daniel. Hope it help!
