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melomori [17]
3 years ago
15

Need help with these 3 questions please explain how you do It. Thx!

Mathematics
1 answer:
Ilya [14]3 years ago
4 0
1. Observe that the f(t) is change by 4 per time t => there's a acceleration of 4 => f''(t) = 4;  Take the derivative of it we can get a velocity function. f'(t) = 4t + c. Since the velocity from 100 to 80 is -20 (average), this means at t = 0, f'(0) = -22 => f'(t) = 4t - 22; Take the derivative again to get the position function: f(t) = 2t^2 - 22t + d, here d = 100 should be trivial. So, the function that models the relationship is    f(t) = 2t^2 - 22t + 100.

2. By the compound interest formula:
    A = P (1 + r/n)^(nt) , since it's yearly, so n = 1;
    results A(t) = 100 (1+0.12)^t.

3. The average rate of change is basically finding the slope, m = y1 - y2 / x1 - x2.
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3x+5=4 two step equations
s344n2d4d5 [400]

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x = -1/3

Step-by-step explanation:

Move 5 to the other side of the equation

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7 0
3 years ago
A spotlight is aimed at an angle of 50° up
Sophie [7]
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2 years ago
Does the table represent an exponential function? Explain.
Ede4ka [16]

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Step-by-step explanation:

We have a set of ordered pairs of the form (x, y)

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This means that:

\frac{y_2}{y_1}=\frac{y_3}{y_2}=\frac{y_4}{y_3}=by1y2=y2y3=y3y4=b

This is: y_2=by_1y2=by1

Now we have this set of points {(-1, -5), (0, -3), (1, -1), (2, 1)}

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\begin{gathered}\frac{y_2}{y_1}=\frac{-3}{-5}=\frac{3}{5}\\\\\frac{y_3}{y_2}=\frac{-1}{-3}=\frac{1}{3}\\\\\frac{3}{5}\neq \frac{1}{3}\end{gathered}y1y2=−5−3=53y2y3=−3−1=3153=31

Then the values of y are not multiplied by a constant amount "b"

5 0
3 years ago
What is the directrix of the parabola defined by 1/4(y+3)=(x-2)^2
Charra [1.4K]
This is a parabola which opens upwards and the directrix will be of the form  
y = k

the general form is 

4p(y - k) = (x - h)^2   we have:-

1/4(y + 3) = (x - 2)^2

so the vertex is at (2, -3)

4p = 1/4  so p =  1/16

so the focus will be at (2 , -2 15/16)

and directrix is  y = -3 1/16
4 0
3 years ago
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