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-BARSIC- [3]
3 years ago
12

Simplify each expression.

Mathematics
1 answer:
lutik1710 [3]3 years ago
4 0

Answer:

1. 80

2. 18.9

3. 7

4. 146

5. 2

6. 4

Step-by-step explanation:

1. 6+4=10

10×8=80

2. 3.6×4.5= 16.2

16.2+2.7= 18.9

3. 3+2=5

5×2= 10

17-10=7

4. 4×3=12^2

12×12=144

144+2= 146

5. 3+2=5

5×6=30

30÷15=2

6. 5×2= 10

40÷10=4

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Oliga [24]
Get all your variables on same side and solve x=-2
4 0
3 years ago
Diana has 1 square yard of fabric she will make one pillow that requires 3/8 square yard of fabric and another pillow that requi
Scilla [17]

Answer:

<h2>Diana uses 5/8 square yard of fabric for both pillows.</h2><h2>There remains 3/8 square yard of fabric.</h2>

Step-by-step explanation:

Givens

  • The total amount of fabric is 1 square yard.
  • One pillow requires 3/8 square yard of fabric.
  • A second pillow requires 2/8 square yard of fabric.

To find the total amount of fabric Diana used, we must sum those fractions

\frac{3}{8} +\frac{2}{8}=\frac{5}{8}

Diana uses 5/8 square yard of fabric for both pillows.

Now, we subtract to find the remaining amount of fabric

1-\frac{5}{8}=\frac{8-5}{8}=\frac{3}{8}

Therefore, there remains 3/8 square yard of fabric.

4 0
3 years ago
Given the force field F, find the work required to move an object on the given oriented curve. F = (y, - x) on the path consisti
timofeeve [1]

Answer:

0

Step-by-step explanation:

We want to compute the curve integral (or line integral)

\bf \int_{C}F

where the force field F is defined by

F(x,y) = (y, -x)

and C is the path consisting of the line segment from (1, 5) to (0, 0) followed by the line segment from (0, 0) to (0, 9).

We can write  

C = \bf C_1+C_2

where  

\bf C_1 =  line segment from (1, 5) to (0, 0)  

\bf C_2 = line segment from (0, 0) to (0, 9)

so,

\bf \int_{C}F=\int_{C_1}F+\int_{C_2}F

Given 2 points P, Q in the plane, we can parameterize the line segment joining P and Q with

<em>r(t) = tQ + (1-t)P for 0 ≤ t ≤ 1 </em>

Hence \bf C_1 can be parameterized as

\bf r_1(t) = (1-t, 5-5t) for 0 ≤ t ≤ 1

and \bf C_2 can be parameterized as

\bf r_2(t) = (0, 9t) for 0 ≤ t ≤ 1

The derivatives are

\bf r_1'(t) = (-1, -5)

\bf r_2'(t) = (0, 9)

and

\bf \int_{C_1}F=\int_{0}^{1}F(r_1(t))\circ r_1'(t)dt=\int_{0}^{1}(5-5t,t-1)\circ (-1,-5)dt=0

\bf \int_{C_2}F=\int_{0}^{1}F(r_2(t))\circ r_2'(t)dt=\int_{0}^{1}(9t,0)\circ (0,-9)dt=0

In consequence,

\bf \int_{C}F=0

6 0
4 years ago
Simplify the expression by combining like terms
Crazy boy [7]
-1/4d+f
Hope this helps

7 0
2 years ago
Square root of 25/16 - square rot of 36/25
muminat
Square root of 25/16 is 5/4
square root of 36/25 is 6/5

square root of 25/16 - square root of 36/25 = 5/4 - 6/5 = (25 - 24)/20 = 1/20
8 0
3 years ago
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