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Aliun [14]
3 years ago
7

In triangle GHI, HI=GH, angle IHG=3x+4 and angle IGH=2x-24. What is angle HIG

Mathematics
2 answers:
Vesna [10]3 years ago
8 0

Answer: 2x - 24

Step-by-step explanation:

Sum of angle in a triangle is 180° and since two sides of the triangle are equal, two angles will also be the same.

The two equal angles will be the base angle IGH and HIG

Since IGH = 2x - 24, HIG = 2x - 24

nadya68 [22]3 years ago
4 0
Because HI=HG, ∠IGH=∠HIG=2x-24
the three interior angles of a triangle make a total of 180, so
(3x+4)+(2x-24)+(2x-24)=180
7x-44=180
7x=224
x=32
so ∠HIG=2x-24=2*32-24=40
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Calculator
Sedaia [141]

Check the picture below.

so let's find the lengths of those two sides in red, since are the length and width of the rectangle.

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-3}~,~\stackrel{y_2}{6})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d = \sqrt{[-3-(-6)]^2+[6-3]^2}\implies d=\sqrt{(-3+6)^2+(6-3)^2} \\\\\\ d=\sqrt{9+9}\implies \boxed{d=\sqrt{18}} \\\\[-0.35em] ~\dotfill

\bf ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-2}~,~\stackrel{y_2}{-1})~\hfill d=\sqrt{[-2-(-6)]^2+[-1-3]^2} \\\\\\ d=\sqrt{(-2+6)^2+(-1-3)^2}\implies d=\sqrt{16+16}\implies \boxed{d=\sqrt{32}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{area of the rectangle}}{(\sqrt{18})(\sqrt{32})}\implies \sqrt{18\cdot 32}\implies \sqrt{576}\implies 24

7 0
3 years ago
Determine the values of c so that the following functions represent joint probability distributions of the random variables X an
Anna11 [10]

Answer:

The joint probility density will be c = 1/36

The joint probability distribution will be c = 1/15

Step-by-step explanation:

For step by step explanation see the pucture attached

7 0
2 years ago
Read 2 more answers
The sum of angle V and angle W is 90 degrees. If cos W = 5/13, what is sin V? A. 5/13 B. 12/13 C.12/5 D. 13/5
Savatey [412]

Answer:

I think the answer to the question should be C

Step-by-step explanation:

3 0
2 years ago
Which equation could generate the curve in the graph below?y=3x^2-2x+1
4vir4ik [10]
If you are asking what is the graph of y = 3x^2 -2x+1.

Then, the attached file would be the answer.

To check, b^2 - 4(a)(c), for each equation and use these facts:

If b^2 - 4(a)(c) = 0, there is only one real root meaning, the graph touches the x-axis only in one point.

If b^2 - 4ac > 0, there are two real roots meaning, the graph touches the x-axis in two different points.

If b2 - 4ac < 0, there are no real roots then the graph does not touch the x-axis. This would be the case for y = 3x^2 - 2x + 1.
Solution:
(-2)^2 -4(3)(1) = 4 - 12 = -8 < 0 will result in not real roots. 

7 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!
lakkis [162]

Answer:

false i think? and true

Step-by-step explanation:


8 0
2 years ago
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