A. yes...it is a function because there is no repeating x values.
B. (5,2)(6,5)...slope = (5 - 2) / (6 - 5) = 3
y = mx + b
slope(m) = 3
(5,2)...x = 5 and y = 2
now we sub
2 = 3(5) + b
2 = 15 + b
2 - 15 = b
-13 = b
so the equation is : y = 3x - 13
when x = 7
y = 3(7) - 13....y = 21 - 13....y = 8
f(x) = 2x + 13...when x = 7
f(7) = 2(7) + 13...f(7) = 14 + 13.....f(7) = 27
the function has a greater value
C. f(x) = 2x + 13....when f(x) = 75
75 = 2x + 13
75 - 13 = 2x
62 = 2x
62/2 = x
31 = x
Answer:
Ivy is 6 years old and Rose is 12 years old.
Step-by-step explanation:
To solve this problem, two variables are necessary since we have two unknown variables: Ivy's age and Rose's age.
Ivy's age will be 
and Rose's age will be 
"Ivy is half as old as her sister":
this will be our <u>fist equation.</u>
"In six years, Ivy will be two-thirds as old as Rose"
in six years Ivy will have 
years, and Rose will have 
years, so for this sentence we have the equation:
this will be our <u>second equation.</u>
Substituting the value of x from the first equation into the second, and solving for y(Rose):
Rose is 12 years old.
and Ivy (using the fist equation):
Ivy is 6 years old.
Answer:
Answer and steps in the pic
Step-by-step explanation:
u > -17
The box plot represents the rate of cars in the Main Street per hour
25 percent of the time, the Main Street have 100 or more cars per hour
<h3>How to determine the proportion of the boxplot?</h3>
From the box plot, we have the following parameter:
The upper quartile of the boxplot is 100
This means that:
Q3 = 100
The upper quartile is the 75% dataset
The actual percentage is then calculated as:
Actual = 100% - 75%
This gives
Actual = 25%
Hence, 25 percent of the time, the Main Street have 100 or more cars per hour
Read more about boxplots at:
brainly.com/question/14277132
This kind of problem request the use of harmonic mean:
if t₁ is the Time spent by Jessica, and
t₂, the time spent by Felecia, and t₃ the time spent by both, then the equation of that kind of problem will be:
1/t₁ + 1/t₂ =1/t₃.
t₁ = 1h45 min, t₂ (unknown, to be calculated), t₃ = 1 h, to ease things let' convert the time in minutes
t₁ = 105 min
t₂ = ?(time needed to Felicia to maw the lawn)
t₃ = 60 min
1/105 +1/t₂ = 1/60===> 1/t₂ = 1/60 - 1/105==> 1/t₂ =1/140
& t₂ =140 minutes or t₂ = 2h & 20 min
