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nlexa [21]
3 years ago
12

3.5.2 Test (CSI) Question 6 of 12 Use the area of the rectangle to find the area of the triangle. 5 ft 10 ft O A. The area of th

e triangle is 25 square feet, because the area of the rectangle is 50 square feet O B. The area of the triangle is 25 square feet, because the area of the rectangle is 25 square feet C. The area of the triangle is 50 square feet, because the area of the rectangle is 50 square feet. D. The area of the triangle is 50 square feet, because the area of the rectangle is 100 square feet. SUBMIT PREVIOUS e 99+ Type here to search​
Mathematics
1 answer:
Jlenok [28]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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ared has a checking account. The bank charges 15¢ for each debit card transaction, 25¢ for each check, and $2.25 for each nonban
solniwko [45]
B)He forgot to record and subtract the fee for writing a check

Hope I helped!
~Mathlete12321~
8 0
3 years ago
Use cylindrical coordinates. Find the volume of the solid that lies within both the cylinder x2 y2
Sedaia [141]

Answer:

hello your question is incomplete here is the complete question

Use cylindrical coordinates Find the volume of the solid that lies within both the cylinder x^2 + y^2=16 and the sphere x^2 + y^2 + Z^2= 81

Answer : \frac{4 \pi }{3} [729 - 65\sqrt{65} ]

Step-by-step explanation:

The given data

cylinder  = x^2 + y^2 = 16

sphere = x^2 + y^2 +z^2 = 81

from the given data the solid is symmetric around the xy plane hence we will calculate half the solid volume above the plane then  multiply the sesult by 2

Note : we are restricting our attention to the cylinder  x^2 + y^2 = 16 and also finding the volume inside the sphere which gives bound on the z-coordinate as well

the r parameter goes from 0 to 4

ATTACHED IS THE REMAINING PART OF THE SOLUTION

showing the integration

5 0
4 years ago
Factor this trinomial 4x^2-6x-10 If you can please try to show me how to do it.
lilavasa [31]

Answer:

=2(2x-5)(x+1)

Step-by-step explanation:

So we have the trinomial:

4x^2-6x-10

First, factor out a 2:

=2(2x^2-3x-5)

Now, factor within the parentheses.

To do so, we want to find two numbers. When multiplied, these two numbers must equal (a)(c) and when added, they must equal b

(a)(c) is 2(-5) or -10 and b is -3. So, we want two numbers that when multiplied together gives -10 and when added gives -3.

-5 and 2 works. Therefore:

=2(2x^2-3x-5)

Replace -3x with 2x and -5x:

=2(2x^2+2x-5x-5)

Factor out a 2x for the first two terms. And factor out a negative 5 for the remaining two:

=2(2x(x+1)-5(x+1))

Grouping:

=2(2x-5)(x+1)

And we're done!

8 0
3 years ago
PLS HELP!!!!!!!!!!!!!
stepladder [879]
First, multiply the top equation by 2 and bottom by -3.
60x+60y=900
-60x-75y=-1035
————————
-15y=-135
—————-
-15=-15
y=9

So the answer should be 9.
6 0
3 years ago
Given the Arithmetic series A1+A2+A3+A4 7 + 11 + 15 + 19 + . . . + 91 What is the value of sum?
aivan3 [116]

Answer:

The value of the sum is 1078

Step-by-step explanation:

* Lets revise how to find the sum of the arithmetic series

- In the arithmetic series there is a constant difference between each

 two consecutive terms

- Ex:

# 4 , 9 , 14 , 19 , 24 , .......... (+ 5)

# 25 , 15 , 5 , -5 , -15 , .......... (-10)

- So if the first term is a and the constant difference between each two

  consecutive terms is d, then

  U1 = a , U2 = a + d , U3 = a + 2d , U4 = a + 3d , ..........

- Then the nth term is Un = a + (n - 1)d

- The sum of n terms is Sn = n/2[a + L] , where L is the last term in

 the series

* Lets solve the problem

∵ The arithmetic series is 7 + 11 + 15 + 19 + ......................... + 91

∴ The first term (a) is 7

∴ The last term is (L) 91

- Lets find the constant difference

∵ 11 - 7 = 4 and 15 - 11 = 4

∴ The constant difference (d) is 4

- Lets find the sum of the series from 7 to 91

∵ Sn = n/2[a + L]

∵ a = 7 and L = 91

∴ Sn = n/2[7 + 91]

- We need to know how many terms in the series

∵ L is the last term and equals 91 lets find its position in the series

∵ Un = a + (n - 1)d

∵ a = 7 , d = 4 and Un = 91

∴ 91 = 7 + (n - 1)(4) ⇒ subtract 7 from both sides

∴ 84 = (n - 1)(4) ⇒ divide both sides by 4

∴ 21 = n - 1 ⇒ add 1 to both sides

∴ n = 22

∴ The number of the terms in the series is 22

- Lets find the sum of the 22 terms (S22)

∴ S22 = 22/2[7 + 91]

∴S22 = 11[98] = 1078

* The value of the sum is 1078

4 0
3 years ago
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