3.5.2 Test (CSI) Question 6 of 12 Use the area of the rectangle to find the area of the triangle. 5 ft 10 ft O A. The area of th
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Convert to vertex form
or easier
for y=ax²+bx+c
the x value of the vertex is
and the y value is found by subsituting the x value in for x
so
y=1x²+4x+11
a=1
b=4
the x value of the vertex is
the y value is found by subsituting -2 for x
y=(-2)²+4(-2)+11
y=4-8+11
y=7
the vertex is (-2,7)
or easier
for y=ax²+bx+c
the x value of the vertex is
and the y value is found by subsituting the x value in for x
so
y=1x²+4x+11
a=1
b=4
the x value of the vertex is
the y value is found by subsituting -2 for x
y=(-2)²+4(-2)+11
y=4-8+11
y=7
the vertex is (-2,7)
The fraction and
are the greatest in each combination.
Explanation:
Comparing the fraction with
and
to find the greatest value.
The fraction and
Thus,
Hence, is the greatest value in this combination.
Also, Comparing the fraction with
and
to find the greatest value.
The fraction and
Thus,
Hence, is the greatest value in this combination.