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3 years ago

Paul purchased a used vehicle that depreciates under a straight-line method.

Mathematics

1 answer:

netineya [11]3 years ago

4 0

Answer:

Option B. $900

Step-by-step explanation:

Let

y ----> the value of the car

x ----> the time in years

we know that

The linear function in slope intercept form is equal to

$y=mx+b$

where

m is the slope or the depreciation rate

b is the y-intercept or initial value of the car

we have

The y-intercept or initial value is equal to

$b=\$5,000$

$y=mx+5,000$

we have the ordered pair (5,500)

substitute the value of x and the value of y of the ordered pair in the linear equation and solve for m

$500=m(5)+5,000$

$5m=500-5,000\\5m=-4,500\\m=-\$900\ per\ year$

Is negative because is a decreasing function

The linear equation is equal to

$y=-900x+5,000$

therefore

It would depreciate $900 each year.

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3 years ago

Factor 3/4 out of 3/4z + 6

Alenkasestr [34]

ANSWER

$\frac{3}{4} z + 6 = \frac{3}{4} (z + 8 )$

EXPLANATION

We want to factor
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so we need to use a trick of multiplying and dividing by the same factor to obtain,

$\frac{3}{4} z + 6 = \frac{3}{4} z + \frac{3}{4} \times \frac{6}{ \frac{3}{4} }$

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We simplify to obtain,

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3 years ago

Read 2 more answers

The mean temperature for the first 4 days in January was 8°C. The mean temperature for the first 5 days in January was 7°C. What

ahrayia [7]

Answer : The 5th day = 3 Celsius

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Now on the first 5 day the average temp is 7

Then the combine temp on the first 5 day is 7 x 5 = 35

Find the 5th day

4 days combine temp + 5th day = the combine temp of 5 days

32 + 5th day = 35
5th day = 35-32
5th day temp = 3C

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3 years ago

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Ivan

Answer:

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Step-by-step explanation:

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