Question

The answer below thanks

Answer 1

Answer:

The equation of the circle having centre (-5,-9) and radius r=3  is

x² + 10 x +y² + 14 y + 65 = 0

Step-by-step explanation:

Explanation:-

From graph  The centre of the circle  C( -5 , -7)

The radius of the circle r = 3cm from the centre of the given circle

The equation of the circle



From graph the centre ( h, k) = ( -5,-7) and r = 3cm

                 $(x-(-5))^2+(y-(-7))^2 = 3^2$

                x² + 10 x +25 +y² + 14 y + 49 =9

              x² + 10 x +25 +y² + 14 y + 49 -9=0

 The equation of the circle

                x² + 10 x  +y² + 14 y + 65 = 0