Answer:
[ry, yr, gy, yg, rg, gr]-Any three picks from this sample space.
Step-by-step explanation:
-The bag contains exactly
marbles.
-He picks one ball without looking, and chooses a second ball without replacing the first:
- If the first is red, the the second is either yellow or green,
- If the first is a yellow, then the second can be red or green,
- If the first is green, then the second can be a red or yellow.
The sample space of the second pick is therefore:
[ry, yr, gy, yg, rg, gr]
Hence, any three picks from the sample space are correct possible outcomes.
Numbers starting with a 1 and followed by only 0s (such 10, 100, 1,000,10,000, and so forth) are called powers of ten, and they're easy to represent as "exponents". Powers of ten are the result of multiplying 10 times itself any number of times.
-x - y = 8
2x - y = -1
Ok, we are going to solve this in 2 parts. First we have to solve for one of the variables in one of the equation in terms of the other variable. I like to take the easiest equation first and try to avoid fractions, so let's use the first equation and solve for x.
-x - y = 8 add y to each side
-x = 8 + y divide by -1
x = -8 - y
So now we have a value for x in terms of y that we can use to substitute into the other equation. In the other equation we are going to put -8 - y in place of the x.
2x - y = -1
2(-8 - y) - y = -1 multiply the 2 through the parentheses
-16 - 2y - y = -1 combine like terms
-16 - 3y = -1 add 16 to both sides
-3y = 15 divide each side by -3
y = -5
Now we have a value for y. We need to plug it into either of the original equations then solve for x. I usually choose the most simple equation.
-x - y = 8
-x - (-5) = 8 multiply -1 through the parentheses
-x + 5 = 8 subtract 5 from each side
-x = 3 divide each side by -1
x = -3
So our solution set is
(-3, -5)
That is the point on the grid where the 2 equations are equal, so that is the place where they intersect.
Based on the CPCTC theorem, the congruences that are true about the given triangles are:
B. ∠K ≅ ∠S
C. KL ≅ ST
D. JK ≅ RS
<h3>What is the CPCTC Theorem?</h3>
According to the CPCTC theorem states that if two triangles are congruent to each other, then, all their corresponding parts will be congruent to each other.
Given that triangles JKL and RST are congruent to each other, therefore:
∠J ≅ ∠R
∠K ≅ ∠S
∠L ≅ ∠T
JK ≅ RS
KL ≅ ST
JL ≅ RT
Therefore, the congruences that would be true by CPCTC are:
B. ∠K ≅ ∠S
C. KL ≅ ST
D. JK ≅ RS
Learn more about the CPCTC theorem on:
brainly.com/question/14706064
#SPJ1
Answer: Choice A) 90
The upper quartile, aka the third quartile (Q3), is visually represented by the right-side edge of the box, which is at 90 on the number line.