<h3>
Answer: 920</h3>
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Explanation:
The front face is a triangle with area of base*height/2 = 15*8/2 = 60 square feet.
The back face is identical to the front face, so we have another 60 square feet.
The left rectangular wall is 20 ft by 8 ft tall. Its area is 20*8 = 160 ft^2
The right slanted rectangular face is 20 ft by 17 ft. Its area is 20*17 = 340 ft^2
Lastly, the bottom rectangle floor is 15 ft by 20 ft to give an area of 15*20 = 300 ft^2
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To summarize so far
- Front face = 60 ft^2
- Back face = 60 ft^2
- Left face = 160 ft^2
- Right slanted face = 340 ft^2
- Bottom floor = 300 ft^2
Add up those areas to get the overall surface area.
60+60+160+340+300 = 920
Answer:
<em>(1, 7) </em>
Step-by-step explanation:
y = 3x + 4
y = 6x + 1
6x + 1 = 3x + 4 ⇒ x = 1
y = 3(1) + 4 = 7
<em>(1, 7)</em>
I am honestly not sure about this answer... try Khan Academy. Or, try breaking it down into steps.
I hope this helped... sorry about that. I will try this concept soon. :)
The problem can be solved step by step, if we know certain basic rules of summation. Following rules assume summation limits are identical.




Armed with the above rules, we can split up the summation into simple terms:





=> (a)
f(x)=28n-n^2=> f'(x)=28-2n
=> at f'(x)=0 => x=14
Since f''(x)=-2 <0 therefore f(14) is a maximum
(b)
f(x) is a maximum when n=14
(c)
the maximum value of f(x) is f(14)=196