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____ [38]
3 years ago
5

Solve by substitution please??? Immediate help!

Mathematics
1 answer:
marta [7]3 years ago
3 0
Solve for the first variable in one of the equations, then substitute the result into the other equation.
3. (1/2, -1,2)
4. (2, -4)
You can get step by step at:
https://www.mathpapa.com/algebra-calculator.html
You might be interested in
-8 - x = x - 4x<br> how does x equal to 4 and how do u do this
Over [174]

Answer:

x=4

Step-by-step explanation:

-x=-3x+8

-x+3x=-3x+8+3x

2x=8

2x/2 = 8/2

x = 4

4 0
2 years ago
Due tomorrow! Please
svp [43]
The answer is 79 because 9/10 divided by 71.1 is 79. And if you want to check, you can multiply 9/10 by 79, which will give you 71.1. I hope this helped :)
8 0
2 years ago
If you flip a coin ten times, how many diffrent sequences of heads and tails are possible
nikdorinn [45]

Answer:

I'm pretty sure its D

Step-by-step explanation: Brainliest???

3 0
3 years ago
What property is illustrated by 5*6=6*5
lara [203]
The commutative property 
6 0
3 years ago
Read 2 more answers
1011+111 in binary form
Ann [662]

Answer:

10010

Step-by-step explanation:

1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0

111=1(2)^2+1(2)^1+1(2)^0

So 1011+111 gives us:

1(2)^3+0(2)^2+1(2)^1+1(2)^0

+

1(2)^2+1(2)^1+1(2)^0

-----------------------------------------------------

Combine like terms:

1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0

1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace 2^0 with 1 and 2 with (2)^1:

1(2)^3+1(2)^2+(2)^2+(2)^1(1)

I want a 2^0 number:

1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0

Combine like terms:

1(2)^3+2(2)^2+1(2)^1+0(2)^0

2(2)^2=2^3:

1(2)^3+2^3+1(2)^1+0(2)^0

Combine like terms:

2(2)^3+1(2)^1+0(2)^0

We can rewrite the first term by law of exponents:

2^4+1(2)^1+0(2)^0

1(2)^4+1(2)^1+0(2)^0

So the binary form is:

10010

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

      1     0     1      1

+            1      1      1

------------------------------

     (1)    (1)    (1)

      1     0     1      1

+            1      1      1

------------------------------

     1 0    0     1       0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0
3 years ago
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