Question

Please help me!!

Answer 1

Answer:

$\frac{x^2}{16}+\frac{y^2}{25}=1$

Step-by-step explanation:

The equation of an ellipse with a center at $(h, k)$ and vertices at $(h\pm a, k)$ and $(h, k\pm b)$ is given by $\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$.

Since two vertices are located at (-4, 0) and (0, 5), the other vertices must be located at (4, 0) and (0, -5).

What we know:

• Center of (0, 0)
• From $(h\pm a, k)$, $a$ must be 4
• From $(h, k\pm b)$, $b$ must be 5

Thus, we have:

$\frac{(x-0)^2}{4^2}+\frac{(y-0)^2}{5^2}=1\implies \boxed{\frac{x^2}{16}+\frac{y^2}{25}=1}$