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zzz [600]
3 years ago
7

Can someone please answer the highlighted questions? thanks!

Mathematics
2 answers:
raketka [301]3 years ago
4 0

Answer:

28 = 14 + x,  51 = 38 + x

Step-by-step explanation:

I got both sums because the last part says "is 28" and "is fifty-one," signaling that they each take up one side of the equation. Sum means add (so a + sign) and more than also means add (in this case). X just stands for the numbers not given.

laila [671]3 years ago
4 0

Answer:

1. n+14=28 (14)

2. 38+n= 51 (13)

Step-by-step explanation:

n+14=28

   -14  -14

n=14

38+n=51

-38     -38

n=13

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Noise levels at 5 airports were measured in decibels yielding the following data: 152,154,139,124,120 Construct the 80% confiden
Yuri [45]

Answer:

137.8-1.533\frac{15.595}{\sqrt{5}}=127.108    

137.8+1.533\frac{15.595}{\sqrt{5}}=148.492    

So on this case the 80% confidence interval would be given by (127.108;148.492)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=137.8

The sample deviation calculated s=15.595

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.80 or 80%, the value of \alpha=0.2 and \alpha/2 =0.1, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.1,4)".And we see that t_{\alpha/2}=1.533

Now we have everything in order to replace into formula (1):

137.8-1.533\frac{15.595}{\sqrt{5}}=127.108    

137.8+1.533\frac{15.595}{\sqrt{5}}=148.492    

So on this case the 80% confidence interval would be given by (127.108;148.492)    

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4 years ago
What is the volume of a right circular cylinder with a radius of 4 m and a height of 4 m?
Tems11 [23]
Answer: 50.24

4 • 3.14 = 12.56
12.56 • 4 = 50.24
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3 years ago
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