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padilas [110]
3 years ago
7

Graph the following function and identify any shifts, stretches, and symmetry and x and y intercepts:

Mathematics
1 answer:
Vlad [161]3 years ago
4 0

Answer:

Step-by-step explanation:

The parent function here is y = x^2, whose graph is that of a parabola that opens up and has its vertex at the origin, (0, 0).

Translating this parent graph 3 units to the right and then up by 2 units will produce the desired graph of y = f(x) = (x - 3)^2 + 2.

There are no stretches or symmetry.

y-intercept:  let x = 0 and find y:  9 + 2 = 11.  y-intercept is (0, 11).

x-intercept:  let y = 0 and find x:  (x - 3)^2 + 2 = 0 => (x - 3)^2 = -2.  This has no real roots.  Thus, there are no x-intercepts.

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Step-by-step explanation:

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1 + 2 = 3

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Given the function f(x)=x^2-8x+13f(x)=x, determine the average rate of change of the function over the interval −1≤x≤6.
Ann [662]

Given:

Consider the given function is:

f(x)=x^2-8x+13

To find:

The average rate of change of the function over the interval -1\leq x\leq 6.

Solution:

The average rate of change of the function f(x) over the interval [a,b] is:

m=\dfrac{f(x_2)-f(x_1)}{x_2-x_1}

We have,

f(x)=x^2-8x+13

At x=-1,

f(-1)=(-1)^2-8(-1)+13

f(-1)=1+8+13

f(-1)=22

At x=6,

f(6)=(6)^2-8(6)+13

f(6)=36-48+13

f(6)=1

Now, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is:

m=\dfrac{f(6)-f(-1)}{6-(-1)}

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Therefore, the average rate of change of the function f(x) over the interval -1\leq x\leq 6 is -3.

6 0
3 years ago
Find the value of x.
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Answer:

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Substitute:

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4 years ago
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