Given equation is

The given equation is in the form of

a^2= 16 , so a=4
b^2 = 9 so b= 4
The value of 'a' is greater than the value of 'b'
So it is a Horizontal hyperbola
First two graphs are horizontal hyperbola
Here center is (h,k)
h= 5 and k =2 from the given equation
So center is (5,2)
Now we find vertices
Vertices are (h+a,k) and (h-a,k)
We know h=5, k=2 and a=4
So vertices are (9,2) and (1,2)
Second graph having same vertices and center
The correct graph is attached below
<span>This is an java command program.
String 1 is stands for str1= '' forest '' accepted within quote marks.
String 2 is stands for str1= '' school'' accepted within quote marks
the command compareto will cause the output will display as shown below :
str1.compareto(str2); when run this command
we will get the output like this ;
forest
school
==================================================
the model program is like this;
{
String str1 = " forest " ;
String str2 = "school ";
System.out.println();
System.out.println("String 1: " + str1);
System.out.println("String 2: " + str2);</span>
I’m not sure but good luck
Answer: 23
Step-by-step explanation: