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icang [17]
3 years ago
8

Hi, this is for a poll

Mathematics
1 answer:
Oxana [17]3 years ago
8 0

Answer:

Florida - Fort Walton Beach

Step-by-step explanation:

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What is equivalent to <img src="https://tex.z-dn.net/?f=%283%5E6%293" id="TexFormula1" title="(3^6)3" alt="(3^6)3" align="absmid
kherson [118]

For this case we must indicate an expression equivalent to:

(3 ^ 6) ^ 3

For properties of powers we have to:

(a ^ n) ^ m = a ^ {n * m}

So, the above expression can be rewritten as:

(3 ^ 6) ^ 3 = 3^{6*3} = 3^{18}

Thus, the resulting expression is: 3^{ 18}

Answer:

3^{ 18}

Option D

8 0
3 years ago
One of two complementary angles is 12 degrees greater than the other. Find the measure of the larger angle.
stiks02 [169]

Answer:

39,51

Step-by-step explanation:

Complementary angles add to 90 degrees

Let one angle be x

The other angle is x+12

x+ x+12 = 90

Combine like terms

2x+12 = 90

Subtract 12 from each side

2x+12-12 = 90-12

2x = 78

Divide each side by 2

2x/2 = 78/2

x =39

The other angle is 39+12 =51

8 0
3 years ago
the ratio of the number of Annes pencils to the number of jasons pencils is 4:3. Anne has 100 pencils how many pencils does Jaso
S_A_V [24]

Answer:

Jason has 75 pencils.

Step-by-step explanation:

In order to get from 4 to 100, you must multiply by 25 (100/4 = 25). And in order to find the amount of pencils Jason has, you must have an equivalent ratio. So you have to also multiply 3 by 25, 3 * 25 = 75. Jason has 75 pencils.

4 0
3 years ago
Arrange the steps to solve this system of linear equations in the correct sequence.
Gwar [14]

Answer:

x=-3

y=1

Step-by-step explanation:

x+y=-2...(1)

2x-3y=-9...(2)

In equation (1) make x the subject of formula by subtracting y from both sides

x=-2-y...(3)

Substitute (3) into (2)

2(-2-y)-3y=-9

Open the bracket

-4-2y-3y=-9

Collect like terms

-2y-3y=-9+4

-5y=-5

Divide both sides by-5

y=1

Substitute y=1 into(3)

x=-2-1

x=-3

Therefore,x=-3,y=1

7 0
3 years ago
Evaluate this equation
alexgriva [62]

Given the integral

\displaystyle \int \tan(3x) \, dx

first substitute y = 3x and dy = 3 dx :

\displaystyle \int \tan(3x) \, dx = \frac13 \int \tan(y) \, dy

then rewrite tan(y) = sin(y)/cos(y) and substitute z = cos(y) and dz = -sin(y) dy :

\displaystyle \frac13 \int \frac{\sin(y)}{\cos(y)} \, dy = -\frac13 \int \frac{dz}z

Recall that 1/z is the derivative of ln|z|. Then back-substitute to get the result in terms of x :

\displaystyle -\frac13 \int \frac{dz}z = -\frac13 \ln|z| + C

\displaystyle \frac13 \int \tan(y) \, dy = -\frac13 \ln|\cos(y)| + C

\displaystyle \boxed{\int \tan(3x) \, dx = -\frac13 \ln|\cos(3x)| + C}

4 0
2 years ago
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