Answer:
speed=d/t
let him cover x distance while walking
running d=4.5-x
s1=x/0.5 km/hr....(1)
s2=4.5-x//5/12.....(2)
atq.....s2=2+s1
s1=2x
s2=54-12x/5
by eqn 1 and 2
s1+s2=2x+54-12x/5
putting value of s2
s1+2+s1=2x+54-12x/5....taking LCM =5
10s1+10= 10x+54-12x
as s1=2x
10s1+10= -2x+54
10s1+10=-s1+54
11s1=44
speed when walking=4km/hr
243 + 62-28 = n
243 + 34 = n
277 = n
n= 277
Answer:
0.08
Step-by-step explanation:
Answer:
ummmmmmmmmmmmmmmmm
Step-by-step explanation:
hmmmmmmmmmmmm
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