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2 years ago

What is the equation of the graph

Mathematics

1 answer:

balandron [24]2 years ago

4 0

Answer:

y=6^x-2

Step-by-step explanation:

Start with the parent function, a^x. The graph looks like it has been translated b units down, so our function is a^x+b. Now at x=0, y=-2. So b=-2. Next at x=1, y=3. 3=a^(1)-2, a=6. y=6^x-2 is the equation

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Which postulate or theorem proves that these two triangles are

melamori03 [73]

Answer: AAS

Step-by-step explanation:

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1 year ago

Simplify the product. (5 − 6)(2 + 7)

Nat2105 [25]

5 - 6 = -1
2 + 7 = 9
-1 × 9 = -9

-9 would be the simplified answer.

Hope this helps!

8 0

2 years ago

WILL CHOOSE BRAINLIEST

algol [13]

Answer:

This is the answer if any problem just ask me

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2 years ago

The weight of an adult swan is normally distributed with a mean of 26 pounds and a standard deviation of 7.2 pounds. A farmer ra

Snezhnost [94]

Let $X$ denote the random variable for the weight of a swan. Then each swan in the sample of 36 selected by the farmer can be assigned a weight denoted by $X_1,\ldots,X_{36}$ , each independently and identically distributed with distribution $X_i\sim\mathcal N(26,7.2)$ .

You want to find

$\mathbb P(X_1+\cdots+X_{36}>1000)=\mathbb P\left(\displaystyle\sum_{i=1}^{36}X_i>1000\right)$

Note that the left side is 36 times the average of the weights of the swans in the sample, i.e. the probability above is equivalent to

$\mathbb P\left(36\displaystyle\sum_{i=1}^{36}\frac{X_i}{36}>1000\right)=\mathbb P\left(\overline X>\dfrac{1000}{36}\right)$

Recall that if $X\sim\mathcal N(\mu,\sigma)$ , then the sampling distribution $\overline X=\displaystyle\sum_{i=1}^n\frac{X_i}n\sim\mathcal N\left(\mu,\dfrac\sigma{\sqrt n}\right)$ with $n$ being the size of the sample.

Transforming to the standard normal distribution, you have

$Z=\dfrac{\overline X-\mu_{\overline X}}{\sigma_{\overline X}}=\sqrt n\dfrac{\overline X-\mu}{\sigma}$

so that in this case,

$Z=6\dfrac{\overline X-26}{7.2}$

and the probability is equivalent to

$\mathbb P\left(\overline X>\dfrac{1000}{36}\right)=\mathbb P\left(6\dfrac{\overline X-26}{7.2}>6\dfrac{\frac{1000}{36}-26}{7.2}\right)$
$=\mathbb P(Z>1.481)\approx0.0693$

5 0

2 years ago

A t shirt maker wants to open his first store.If he chooses the store on Main Street he will pay 650 in rent and will charge 32$

ch4aika [34]

Answer: 35 t shirts

Step-by-step explanation:

Let number of t shirts be x

Let profit made be y

On main street, the store costs $650,

Selling the t shirt at $32 per 1

He would make a revenue of 32x

Profit = revenue - cost accrued

y1 = 32x - 650

On Broad street, the store costs $440,

Selling the t shirt at $26 per 1

He would make a revenue of 26x

Profit = revenue - cost accrued

y2 = 26x - 440

To make same profit on either location

y1 = y2

32x - 650 =26x - 440

32x -26x = -440+650

6x = 210

x = 210/6

= 35 t shirts

5 0

2 years ago