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MArishka [77]
3 years ago
7

What is the solution to the system of equations?

Mathematics
1 answer:
Kipish [7]3 years ago
6 0

Answer:

Step-by-step explanation:

y = -3x - 2

5x + 2y = 15

5x + 2(-3x -2) = 15

5x -6x - 4 = 15

-x - 4 = 15

-x = 19

x = -19

y = -3(-19) - 2

y = 57 - 2

y = 55

(-19, 55)

solution is b

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Let H = Hailey, M = Megan, B = Bailey

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A type of long-range radio transmits data across the Atlantic Ocean. The number of errors in the transmission during any given a
Marianna [84]

Answer:

32.33% probability of having at least 3 erros in an hour.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

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The mean number of errors is 2 per hour.

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Either you have 2 or less errors in an hour, or we have at least 3 errors. The sum of the probabilities of these events is decimal 1. So

P(X \leq 2) + P(X \geq 3) = 1

We want P(X \geq 3)

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P(X \geq 3) = 1 - P(X \leq 2)

In which

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P(X = 0) = \frac{e^{-2}*(2)^{0}}{(0)!} = 0.1353

P(X = 1) = \frac{e^{-2}*(2)^{1}}{(1)!} = 0.2707

P(X = 2) = \frac{e^{-2}*(2)^{2}}{(2)!} = 0.2707

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.1353 + 0.2707 + 0.2707 = 0.6767

P(X \geq 3) = 1 - P(X \leq 2) = 1 - 0.6767 = 0.3233

32.33% probability of having at least 3 erros in an hour.

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Answer:

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