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3 years ago

Which expression shows

Mathematics

2 answers:

Genrish500 [490]3 years ago

7 0

Answer:

8 less than the product of 4 times 7 is....

8-4×7.

d1i1m1o1n [39]3 years ago

6 0

Answer:

i think b cuz it shows 8 less means minus than product of 4 × 7 so it shows the answer b

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The width of a rectangle is 5n - 3.5 feet and the length is 3.5n + 9 feet. Find the perimeter of the rectangle.

juin [17]

Answer:

17n+11

Step-by-step explanation:

Formula For Perimeter Of Rectangle: 2(Length) + 2(Width)

Length = 3.5n + 9

Width = 5n - 3.5

____________________________________________________

-> 2(Length) + 2(Width)

-> 2(3.5n+9) + 2(5n-3.5)

*distribute*

-> (7n+18) + (10n-7)

*distribute*

->7n+18+10n-7

->17n-11

7 0

3 years ago

Write the ratio of hands to cellphones in simplest form. it was 8 hands and 4 phones

Lapatulllka [165]

Answer:

The ratio is 2:1

Step-by-step explanation:

This is since there are 2 times the amount of hands as there are phones

4 0

3 years ago

Combine like terms in the expression below.<br> 4x+4.44xy+22y+32y−19x+9.94

adoni [48]

Add the whole numbers, including the decimals, then the variables like y and x.

5 0

3 years ago

Read 2 more answers

You can build a dog house in 6 hours. And you work 8 hours how long would it take you to build 10 dog house.

Alexus [3.1K]

Seven days and a half

For you work 8 hours a day
It takes you 6 hours to per each
You wanna make 10
10 by 6 is 60 on 8 = 7.5

Best luck!

Wise

5 0

3 years ago

Read 2 more answers

Fission tracks are trails found in uranium-bearing minerals, left by fragments released during fission events. An article report

Harlamova29_29 [7]

Answer:

Mean track length for this rock specimen is between 10.463 and 13.537

Step-by-step explanation:

99% confidence interval for the mean track length for rock specimen can be calculated using the formula:

M± $\frac{t*s}{\sqrt{N}}$ where

M is the average track length (12 μm) in the report
t is the two tailed t-score in 99% confidence interval (2.977)
s is the standard deviation of track lengths in the report (2 μm)
N is the total number of tracks (15)

putting these numbers in the formula, we get confidence interval in 99% confidence as:

12± $\frac{2.977*2}{\sqrt{15}}$ =12±1.537

Therefore, mean track length for this rock specimen is between 10.463 and 13.537

4 0

3 years ago