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mr_godi [17]
3 years ago
15

Use the substitution method to solve the system of equations. y=4x 8x+y=18

Mathematics
2 answers:
RUDIKE [14]3 years ago
4 0

Answer:

x=3/2, y=6

Step-by-step explanation:

plz mark brainliest!

balu736 [363]3 years ago
4 0

Answer:

Step-by-step explanation:

y = 4x

8x + y = 18

8x + 4x = 18

12x = 18

x = 18/12 = 3/2

y = 4(3/2)= 6

(3/2, 6)

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P= -24<br>q= 12<br>r= -6<br><br>a. (pxq):(q+r)<br>b. (pxr):(r-q)<br><br>what the answer?​
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Step-by-step explanation:

a. ( p × q ) ( q + r )

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b. ( p × r ) ( r - q )

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2 years ago
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Read 2 more answers
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
Any suggestions or answers
OLEGan [10]
2nd answer.

any pts in the shaded region satisfies your simultaneous equation.
5 0
3 years ago
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