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2 years ago

Pls help math problem pls

Mathematics

1 answer:

Dovator [93]2 years ago

5 0

Answer: The fourth choice

Step-by-step explanation:

(f - g)(x) = f(x) - g(x) = 4 $x^{2}$ - 5x - (3 $x^{2}$ + 6x - 4) = $x^{2}$ - 11x + 4

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Problem page the price of a notebook has dropped to $3.20 today. Yesterday's price was $3.45 . Find the percentage decrease. Rou

Anna11 [10]

Yesterday's price of notebook = $3.45

Today's price of notebook = $3.20

We have to determine the percentage decrease in the cost of notebook.

Percentage decrease = (Decrease $\div$ Old price) $\times 100$

So, percentage decrease = $\frac{3.45-3.20}{3.45} \times 100$

= $\frac{0.25}{3.45} \times 100$

= 7.246%

= 7.25%

Therefore, there is 7.25% of decrease in the cost of the notebook.

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3 years ago

An angle measures 156° less than the measure of its supplementary angle. What is the measure of each angle?

Advocard [28]

Answer:

Angle 1: 168

Angle 2: 12

Explanation:

I did the math! basically, i did 168-156, and got 12. Then i added, 168+12, and got 180. So i know that both angles together make 180 degrees, which is the definition of supplementary angles.

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4 years ago

Larry used a pattern of colors to make a cube train.he used a red cube ,blue cube a red cube and another red cube. before he sta

Gelneren [198K]

He used 3 red cubes.....

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4 years ago

Read 2 more answers

A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f

Andrews [41]

Answer:

$A = \frac{P}{r}\left( e^{rt} -1 \right)$

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

$\frac{dA}{rA+P} = dt$

Integration on both sides gives

$\int \frac{dA}{rA+P} = \int dt$

where $c$ is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

$\int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c$