What happens to light when it passes from a gas to a liquid or solid material?
2 answers:
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Since you know a = 5√2, start by plugging that into your other equation, 2a = √2x to get an equation where x is the only variable you need to solve for:
There are two ways of solving for x:
1) Remember when you simplify radicals, you break what's underneath the radical into smaller factors. If a factor repeats under the square root, you can take two of them out and put one of them outside the radical sign (see picture for example). For this problem, you would be doing the reverse of simplifying. You have a 10 on the outside on the left of the equal sign, but a 2 underneath on both sides. If the 10 was taken out, that means there had to be two 10's underneath the radical to begin with. Those two tens would have been multiplied since they are factors, so 10 x 10 = 100. That means x = 100.
2) Solve it algebraically. Square both sides, simplify, then divide by 2:
Answer: x = 100
There are two ways of solving for x:
1) Remember when you simplify radicals, you break what's underneath the radical into smaller factors. If a factor repeats under the square root, you can take two of them out and put one of them outside the radical sign (see picture for example). For this problem, you would be doing the reverse of simplifying. You have a 10 on the outside on the left of the equal sign, but a 2 underneath on both sides. If the 10 was taken out, that means there had to be two 10's underneath the radical to begin with. Those two tens would have been multiplied since they are factors, so 10 x 10 = 100. That means x = 100.
2) Solve it algebraically. Square both sides, simplify, then divide by 2:
Answer: x = 100
Answer:
3. Homogenous and unsaturated
Explanation:
Since your given information mentions 50 grams of solvent and 5 grams of solute, you must double each amount because "
Table G Solubility Curves" in the Regents Chemistry Reference Table notates curves based off of 100 g samples of water. Therefore, you must look for how soluble 10 grams of KCl is in 100 grams of water at 25 degrees Celsius.
As the picture shows, 10 grams of KCl is well below the curve for saturation, meaning that the solution is undersaturated.
As for the second part of the answer, we can tell that the solution is homogenous (of uniform composition) because there is no possibility of the salt, KCl, falling out of solution and making the mixture heterogenous (of mixed composition).
Putting all of those ideas together, we can tell that the answer to this question is:
3. Homogenous and unsaturated
Answer:
3.5 K
Explanation:
When a sample of a substance releases heat energy, its temperature decreases according to the equation:
where
Q is the heat energy released
m is the mass of the substance
C is the specific heat capacity
is the initial temperature
is the final temperature
For the block of brass in this problem, we have:
m = 0.1 kg is the mass
Q = -56.4 J is the heat energy released (negative since it is released)
C = 380 J/kg K is the specific heat capacity of brass
is the initial temperature
Solving for , we find the final temperature: