20% = 0.20.2 * 1630 = 326
Answer:
14/29. reduced form............
Answer:
56/65
Step-by-step explanation:
First, we know that cos(a-b) = cos(a)cos(b) + sin(a)sin(b)
We know what sin(a) and sin(b) are, and to get cos(a), we can take the equation sin²a + cos²a = 1
Thus,
(12/13)² + cos²a = 1
1 - (12/13)² = cos²a
1- 144/169 = cos²a
cos²a = 25/169
cos(a) = 5/13
Similarly,
(3/5)² + cos²b = 1
1 - (3/5)² = cos²b
1 - 9/25 = cos²b
cos²b = 16/25
cos(b) = 4/5
Our answer is
cos(a-b) = cos(a)cos(b) + sin(a)sin(b)
cos(a-b) = (5/13)(4/5) + (12/13)(3/5)
cos(a-b) = 20/65 + 36/65
cos(a-b) = 56/65
The question is not complete because it is not written correctly
Complete Question:
The drama club is holding auditions for five different parts in a one act play. If 9 people audition, how many ways can the roles be assigned?
a. 362,880
b. 15,120
c. 126
d. 120
Answer:
b. 15,120
Step-by-step explanation:
In other to solve the question above, we would use the formula for permutation.
This is because when assigning 5 DIFFERENT roles to 9 people, the order of assigning the roles is important. The formula for permutation, is used when order is involved.
Permutation (n, r) = nPr = n!/(n - r)!
In the above question,
n = 9 people
r = 5 different parts
9P5 = 9!/(9 - 5)!
= 9!/4! = 9×8×7×6×5×4×3×2×1/ 4×3×2×1
= 362880/ 24
= 15,120
Therefore, the number of ways that the roles can be assigned is 15,120 ways
