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ahrayia [7]
3 years ago
5

Help please! Calculate the exact value of cos (a-b) given that sin a= 12/13 with pi/2

Mathematics
1 answer:
zloy xaker [14]3 years ago
4 0

Answer:

56/65

Step-by-step explanation:

First, we know that cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

We know what sin(a) and sin(b) are, and to get cos(a), we can take the equation sin²a + cos²a = 1

Thus,

(12/13)² + cos²a = 1

1 - (12/13)² = cos²a

1- 144/169 = cos²a

cos²a = 25/169

cos(a) = 5/13

Similarly,

(3/5)² + cos²b = 1

1 - (3/5)² = cos²b

1 - 9/25 = cos²b

cos²b = 16/25

cos(b) = 4/5

Our answer is

cos(a-b) = cos(a)cos(b) + sin(a)sin(b)

cos(a-b)  = (5/13)(4/5) + (12/13)(3/5)

cos(a-b)  = 20/65 + 36/65

cos(a-b)  = 56/65

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The Cartesian product is a subset of it. Alternatively, a collection of points (ordered pairs). In other words, the collection of the ordered pair is defined as the relationship between the two sets, where the ordered pair is generated by the object from each set.

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