Ask question

Ask question

All categories

3 years ago

13

Consider the vector b⃗ with length 4.00 m at an angle 23.5∘ north of east. what is the y component by of this vector? express yo

ur answer in meters to three significant figures.

1 answer:

stepan [7]3 years ago

4 0

Assuming "y" is north, the y-component is
.. (4.00 m)*sin(23.5°) ≈ 1.59 m

You might be interested in

Suppose that you measure a pen to be 10.5cm long. Convert this to meters.

Vinvika [58]

<span>the answer: the following methods are the main rule according to the convertions we know this followin table: km hm dam m dm cm mm. if we want to change or convert any value, cm to meters, meters to km, or anything else, just follow this: converting dm (decimeter) to m, just multiply the number by 0.1, converting cm (centimeter) to m, just multiply the number by 0.01, converting mm (millimeter) to m, just multiply the number by 0.001, in our case, we have: convert 10.5cm to meters, so it is 10.5 x 0.01 =0.105 meters</span>

6 0

3 years ago

Read 2 more answers

1. Find the vertex of the following: y = (x - 4)(x - 10) *

horsena [70]

Answer:

1. (7,-9)

2. (4,0) and (10,0)

3. (3,0) and (-3,0)

4. (0,-9)

5. (-1,-32)

Step-by-step explanation:

To find the vertex use the formula

$\frac{-b}{2a}$

First make the equation into a quadratic equation.

$(x-4)(x-10)\\x^{2} -10x-4x+40\\x^{2} -14x+40$

Now it is in the form

$ax^{2} +bx+c=0$

Now we can substitute the values

$\frac{-(-14)}{2(1)} \\\frac{14}{2} \\7$

Now we have 7 as our x value for the vertex we can substitute for y,

$x^{2} -14x+40=y\\(7)^{2} -14(7)+40=y\\49-98+4=y\\y=-9$

So the vertex for 1 is (7,-9)

To find the intercepts for 2 & 3, they basically already give it to you. You just need to find a value for x for x-4 that will equal it to 0 and another for x for x-10 that will equal it to 0.

$x-4=0\\x=4\\\\x-10=0\\x=10$

4 is slightly different but start the same,

$(x-3)(x+3)\\x^{2}+3x-3x-9\\x^{2}-9$

Here, c (9) just shows the graph move down 9, so the y intercept = 9.

5 is the same process as 1,

$2(x-3)(x+5)\\2(x^{2}+5x-3x-15)\\2(x^{2}+2x-15)\\2x^{2}+4x-30$

Vertex,

$\frac{-(4)}{2(2)} \\\frac{-4}{4} \\-1$

Substitute,

$2x^{2}+4x-30\\2(-1)^{2}+4(-1)-30\\2-4-30\\-32$

So the vertex is (-1,-32)

8 0

3 years ago

Find the perimeter and area of the figure. Round to the nearest tenth if necessary. 33.7 mm; 108 mm2 33.7 mm; 54 mm2 30.7 mm; 50

Deffense [45]

Answer:

Perimeter: 33.7 mm

Area: 54 mm

Step-by-step explanation:

If you do 12 + 9.7 + 12 you will get the perimeter, and to get the area you would use the formula A = $\frac{1}{2}$ x base x height. Since the base is 12 and the height is 9, you would do 12 x 9 x 0.5 to get 54 mm for the area of the triangle.

8 0

3 years ago

Juli2301 [7.4K]

Answer:

I believe the answer is 540* because

Step-by-step explanation:

we start with the fractions, we have 3/4 and 1/4 which makes a whole, to make it easier i added that to 329 to get 330. Then i added 330 to 210 to get 540.

4 0

3 years ago

Read 2 more answers

Help on #6 and if you can #5

alexgriva [62]

You subtract y from 425, I can read #5 or is help

4 0

3 years ago